使用 switch 语句在不同的按钮上播放不同的声音不起作用

Question

当我尝试在不同的按钮上播放不同的声音时，它不适用于 switch 语句。如果“if-else”语句有效，我尝试了同样的事情。有人可以帮我解决我在 switch 语句上做错了什么吗？

var numberOfDrumButtons = document.querySelectorAll(".drum").length;

for (var i = 0; i < numberOfDrumButtons; i++) {
    
    document.querySelectorAll(".drum")[i].addEventListener('click', () => {
    
        var buttonInnerHTML = this.innerHTML;
    
        switch (buttonInnerHTML) {
            case "w":
                var tom1 = new Audio("sounds/tom-1.mp3");
                tom1.play();
                break;
    
            case "a":
                var tom2 = new Audio('sounds/tom-2.mp3');
                tom2.play();
                break;
    
            case "s":
                var tom3 = new Audio('sounds/tom-3.mp3');
                tom3.play();
                break;
    
            case "d":
                var tom3 = new Audio('sounds/tom-4.mp3');
                tom4.play();
                break;
    
            case "j":
                var snare = new Audio('sounds/snare.mp3');
                snare.play();
                break;
    
            case "k":
                var crash = new Audio('sounds/crash.mp3');
                crash.play();
                break;
    
            case "l":
                var kick = new Audio('sounds/kick-bass.mp3');
                kick.play();
                break;
    
            default:
                console.log('buttonInnerHTML');
        }
    
    });

}

Answer 1

问题出在这一行

document.querySelectorAll(".drum")[i].addEventListener('click', () => {

通过将其更改为

解决了它

document.querySelectorAll(".drum")[i].addEventListener('click', function() {

使用 switch 语句在不同的按钮上播放不同的声音不起作用

Playing different sounds on different buttons using switch statements not working

javascript

switch-statement