如何将多个列表合并为 1，但仅合并所有初始列表中的那些元素？

Question

我需要合并 5 个列表，其中任何列表都可以这样为空，以便只有所有 5 个初始列表中的项目都包含在新形成的列表中。

for filter in filters:

    if filter == 'M':
        filtered1 = [] # imagine that this is filled

    if filter == 'V':
        filtered2 = [] # imagine that this is filled

    if filter == 'S':
        filtered3 = [] # imagine that this is filled

    if filter == 'O':
        filtered4 = [] # imagine that this is filled

    if filter == 'C':
        filtered5 = [] # imagine that this is filled

filtered = [] # merge all 5 lists from above

所以现在我需要制作一个列表，其中包含来自所有过滤列表 1-5 的合并数据。我应该怎么做？

Answer 1

给定一些列表 xs1, ..., xs5:

xss = [xs1, xs2, xs3, xs4, xs5]
sets = [set(xs) for xs in xss]
merged = set.intersection(*sets)

这有属性，merged可以任意顺序。

Answer 2

f1, f2, f3, f4, f5 = [1], [], [2, 5], [4, 1], [3]

only_merge = [*f1, *f2, *f3, *f4, *f5]
print("Only merge: ", only_merge)

merge_and_sort = sorted([*f1, *f2, *f3, *f4, *f5])
print("Merge and sort: ", merge_and_sort)

merge_and_unique_and_sort = list({*f1, *f2, *f3, *f4, *f5})
print("Merge, unique and sort: ", merge_and_unique_and_sort)

输出：

Only merge:  [1, 2, 5, 4, 1, 3]
Merge and sort:  [1, 1, 2, 3, 4, 5]
Merge, unique and sort:  [1, 2, 3, 4, 5]

Answer 3

这是最经典的解决方案

filtered = filter1 + filter2 + filter3 + filter4 + filter5

您将一个列表添加到另一个列表，依此类推...

因此，如果 filter1 为 ['a'、'b']，filter3 为 ['c'、'd']，filter4 为 ['e']，那么你会得到：

filtered = ['a', 'b', 'c', 'd', 'e']

如何将多个列表合并为 1，但仅合并所有初始列表中的那些元素？

How to merge multiple lists into 1 but only those elements that were in all of the initial lists?

python

merge

list