Node.js - 如何根据条件合并数组中的对象?
Node.js - How to merge objects inside an array based on condition?
在Node.js中,我有3组数据如
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"dailyData":159392.235451,
"dailyDataInUSC":255.284807
}
]
和
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"monthlyData":159392.235451,
"monthlyDataInUSC":255.284807
},
{
"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
"monthlyData":349392.455451,
"monthlyDataInUSC":655.234807
}
]
和
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"threeMonthsData":159392.235451,
"threeMonthsDataInUSC":255.284807
},
{
"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
"threeMonthsData":349392.455451,
"threeMonthsDataInUSC":655.234807
},
{
"userId":"34sdf34-67j4-54nd-6763-d2ec81e8aaf3",
"threeMonthsData":6789392.455451,
"threeMonthsDataInUSC":905.655807
}
]
我如何根据数组中的 userId
(filter) 将其合并为一个对象。
例如,输出应该像
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"dailyData":159392.235451,
"dailyDataInUSC":255.284807,
"monthlyData":159392.235451,
"monthlyDataInUSC":255.284807,
"threeMonthsData":159392.235451,
"threeMonthsDataInUSC":255.284807
}
]
请帮我实现这个。
const aa = () => {
let aa = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
dailyData: 159392.235451,
dailyDataInUSC: 255.284807
}
];
let bb = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
monthlyData: 159392.235451,
monthlyDataInUSC: 255.284807
},
{
userId: "23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
monthlyData: 349392.455451,
monthlyDataInUSC: 655.234807
}
];
let cc = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
threeMonthsData: 159392.235451,
threeMonthsDataInUSC: 255.284807
},
{
userId: "23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
threeMonthsData: 349392.455451,
threeMonthsDataInUSC: 655.234807
},
{
userId: "34sdf34-67j4-54nd-6763-d2ec81e8aaf3",
threeMonthsData: 6789392.455451,
threeMonthsDataInUSC: 905.655807
}
];
let newArrObj = aa;
bb.forEach(item => {
let index = newArrObj.findIndex(item1 => item1.userId === item.userId);
if (index === -1) {
newArrObj = [...newArrObj, item];
} else {
newArrObj[index] = { ...newArrObj[index], ...item };
}
});
cc.forEach(item => {
let index = newArrObj.findIndex(item1 => item1.userId === item.userId);
if (index === -1) {
newArrObj = [...newArrObj, item];
} else {
newArrObj[index] = { ...newArrObj[index], ...item };
}
});
console.log(newArrObj);
};
spread
, reduce
and findIndex
的组合可以解决问题
- 使用
spread
运算符将原始数组合并为一个数组。
- 使用
reduce
按键对元素进行分组(在本例中为 userId
)
像这样:
const dailyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","dailyData":159392.235451,"dailyDataInUSC":255.284807}];
const monthlyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","monthlyData":159392.235451,"monthlyDataInUSC":255.284807}, {"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3","monthlyData":349392.455451,"monthlyDataInUSC":655.234807}]
const triMonthlyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","threeMonthsData":159392.235451,"threeMonthsDataInUSC":255.284807}, {"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3","threeMonthsData":349392.455451,"threeMonthsDataInUSC":655.234807}, {"userId":"34sdf34-67j4-54nd-6763-d2ec81e8aaf3","threeMonthsData":6789392.455451,"threeMonthsDataInUSC":905.655807}]
const combinedData = [...dailyData, ...monthlyData, ...triMonthlyData].reduce((mergedResult, curElement) => {
let matchingElementIdx = mergedResult.findIndex(ele => ele.userId === curElement.userId);
if (matchingElementIdx !== -1) {
mergedResult[matchingElementIdx] = {...mergedResult[matchingElementIdx], ...curElement};
} else {
mergedResult = [...mergedResult, curElement];
}
return mergedResult;
}, []);
console.log(combinedData);
在Node.js中,我有3组数据如
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"dailyData":159392.235451,
"dailyDataInUSC":255.284807
}
]
和
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"monthlyData":159392.235451,
"monthlyDataInUSC":255.284807
},
{
"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
"monthlyData":349392.455451,
"monthlyDataInUSC":655.234807
}
]
和
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"threeMonthsData":159392.235451,
"threeMonthsDataInUSC":255.284807
},
{
"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
"threeMonthsData":349392.455451,
"threeMonthsDataInUSC":655.234807
},
{
"userId":"34sdf34-67j4-54nd-6763-d2ec81e8aaf3",
"threeMonthsData":6789392.455451,
"threeMonthsDataInUSC":905.655807
}
]
我如何根据数组中的 userId
(filter) 将其合并为一个对象。
例如,输出应该像
[
{
"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
"dailyData":159392.235451,
"dailyDataInUSC":255.284807,
"monthlyData":159392.235451,
"monthlyDataInUSC":255.284807,
"threeMonthsData":159392.235451,
"threeMonthsDataInUSC":255.284807
}
]
请帮我实现这个。
const aa = () => {
let aa = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
dailyData: 159392.235451,
dailyDataInUSC: 255.284807
}
];
let bb = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
monthlyData: 159392.235451,
monthlyDataInUSC: 255.284807
},
{
userId: "23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
monthlyData: 349392.455451,
monthlyDataInUSC: 655.234807
}
];
let cc = [
{
userId: "54c7f3ef-64d4-40de-8100-d2ec81e8aaf3",
threeMonthsData: 159392.235451,
threeMonthsDataInUSC: 255.284807
},
{
userId: "23fs6fds3-34k4-17de-3123-d2ec81e8aaf3",
threeMonthsData: 349392.455451,
threeMonthsDataInUSC: 655.234807
},
{
userId: "34sdf34-67j4-54nd-6763-d2ec81e8aaf3",
threeMonthsData: 6789392.455451,
threeMonthsDataInUSC: 905.655807
}
];
let newArrObj = aa;
bb.forEach(item => {
let index = newArrObj.findIndex(item1 => item1.userId === item.userId);
if (index === -1) {
newArrObj = [...newArrObj, item];
} else {
newArrObj[index] = { ...newArrObj[index], ...item };
}
});
cc.forEach(item => {
let index = newArrObj.findIndex(item1 => item1.userId === item.userId);
if (index === -1) {
newArrObj = [...newArrObj, item];
} else {
newArrObj[index] = { ...newArrObj[index], ...item };
}
});
console.log(newArrObj);
};
spread
, reduce
and findIndex
的组合可以解决问题
- 使用
spread
运算符将原始数组合并为一个数组。 - 使用
reduce
按键对元素进行分组(在本例中为userId
)
像这样:
const dailyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","dailyData":159392.235451,"dailyDataInUSC":255.284807}];
const monthlyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","monthlyData":159392.235451,"monthlyDataInUSC":255.284807}, {"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3","monthlyData":349392.455451,"monthlyDataInUSC":655.234807}]
const triMonthlyData = [{"userId":"54c7f3ef-64d4-40de-8100-d2ec81e8aaf3","threeMonthsData":159392.235451,"threeMonthsDataInUSC":255.284807}, {"userId":"23fs6fds3-34k4-17de-3123-d2ec81e8aaf3","threeMonthsData":349392.455451,"threeMonthsDataInUSC":655.234807}, {"userId":"34sdf34-67j4-54nd-6763-d2ec81e8aaf3","threeMonthsData":6789392.455451,"threeMonthsDataInUSC":905.655807}]
const combinedData = [...dailyData, ...monthlyData, ...triMonthlyData].reduce((mergedResult, curElement) => {
let matchingElementIdx = mergedResult.findIndex(ele => ele.userId === curElement.userId);
if (matchingElementIdx !== -1) {
mergedResult[matchingElementIdx] = {...mergedResult[matchingElementIdx], ...curElement};
} else {
mergedResult = [...mergedResult, curElement];
}
return mergedResult;
}, []);
console.log(combinedData);