在列表中提取生成器的实际输出

Question

我正在尝试从生成器获取实际输出，但我得到的输出是生成器对象。请帮助我实现生成器的实际输出

import spacy
nlp = spacy.load('en')

def lemmatizer(words):
     yield from [w.lemma_ for w in nlp(words)]

list1 = ['birds hanging on street','people playing cards']

a = list(map(lemmatizer,list1))

输出：

a
[<generator object....>,
<generator object....>]

预期输出：

a
['birds hang on street',
'people play card']

Answer 1

使用next从生成器中产生。添加 next 像 a = list(next(map(lemmatizer,list1))) 应该有效。

import spacy
nlp = spacy.load('en')

def lemmatizer(words):
     yield from [w.lemma_ for w in nlp(words)]

list1 = ['birds hanging on street','people playing cards']

a = list(next(map(lemmatizer,list1)))

Answer 2

这在@PatrickArtner 评论的帮助下对我有用

a = list(map(list, map(lemmatizer,list1)))
b = list(map(' '.join, a))

在列表中提取生成器的实际输出

extracting the actual output of generator in a list

python

generator

spacy

yield-from