Arraylist 不添加
Arraylist doesn't add
我有一个关于向 ArrayList 添加元素的问题,我不明白。
结果告诉我它没有添加两台计算机。
有人可以帮助我吗?
Computer computer;
GenerateXML xml;
Parser dom = new Parser();
List computers = new ArrayList();
computer = new Computer("2", "fisso", "Corsair", "Venom 2X", 1029971511, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
computer = new Computer("3", "laptop", "Microsoft", "Surface", 1000091801, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
try {
xml = new GenerateXML(computers);
xml.printToFile("computer.xml");
} catch (ParserConfigurationException | TransformerException exception) {
System.out.println("Errore generate!");
}
try{
computers = dom.parseDocument("computer.xml");
} catch (ParserConfigurationException | SAXException | IOException exception){
System.out.println("Errore parsing!");
}
System.out.println("Numero computers: " + computers.size());
for (int i = 0; i < computers.size(); i++)
System.out.println(computers.get(i));
结果是:
Numero computers: 0
您将计算机初始化为空列表。
List computers = new ArrayList();
然后您将两台计算机添加到列表中。
computer = new Computer("2", "fisso", "Corsair", "Venom 2X", 1029971511, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
computer = new Computer("3", "laptop", "Microsoft", "Surface", 1000091801, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
此时,您的计算机列表将包含两台计算机。列表的大小将是两个。
然后您为第二个 try/catch 块中的计算机列表分配一个新值。通过这样做,您将丢失之前创建和填充的列表。在此之后,计算机将是一个全新的列表。
computers = dom.parseDocument("computer.xml");
我有一个关于向 ArrayList 添加元素的问题,我不明白。 结果告诉我它没有添加两台计算机。 有人可以帮助我吗?
Computer computer;
GenerateXML xml;
Parser dom = new Parser();
List computers = new ArrayList();
computer = new Computer("2", "fisso", "Corsair", "Venom 2X", 1029971511, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
computer = new Computer("3", "laptop", "Microsoft", "Surface", 1000091801, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
try {
xml = new GenerateXML(computers);
xml.printToFile("computer.xml");
} catch (ParserConfigurationException | TransformerException exception) {
System.out.println("Errore generate!");
}
try{
computers = dom.parseDocument("computer.xml");
} catch (ParserConfigurationException | SAXException | IOException exception){
System.out.println("Errore parsing!");
}
System.out.println("Numero computers: " + computers.size());
for (int i = 0; i < computers.size(); i++)
System.out.println(computers.get(i));
结果是:
Numero computers: 0
您将计算机初始化为空列表。
List computers = new ArrayList();
然后您将两台计算机添加到列表中。
computer = new Computer("2", "fisso", "Corsair", "Venom 2X", 1029971511, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
computer = new Computer("3", "laptop", "Microsoft", "Surface", 1000091801, 4.5f, 12, 32, 600, 24.0f, 1900, "Linux", "21-10-2021");
computers.add(computer);
此时,您的计算机列表将包含两台计算机。列表的大小将是两个。
然后您为第二个 try/catch 块中的计算机列表分配一个新值。通过这样做,您将丢失之前创建和填充的列表。在此之后,计算机将是一个全新的列表。
computers = dom.parseDocument("computer.xml");