如何按行对数据框中的元素进行分组
How to group elements in dataframe by row
我有 this code 本质上是将图像的像素转换为 minecraft 中的一个方块，它为您提供了一个“地图”，说明该方块的放置位置，以便在游戏中形成图像：代码生成一个 csv 文件，其中电子表格中的每个单元格对应一个块。
我想改进这一点，不仅输出 csv 文件，还输出一个 txt 文件，其中包含将在游戏中生成图像的 minecraft 命令。
此外，这些命令必须与玩家的 (x, y, z) 有相对位置，这应该通过元组或其他方式在代码中告知。
因此，假设玩家在游戏中位于 0, 0, 0，并且我的 csv 看起来像
这是用于测试的字典形式的相同数据框
{0: {0: 'minecraft:diorite', 1: 'minecraft:diorite', 2: 'minecraft:stone'},
1: {0: 'minecraft:stone', 1: 'minecraft:stone', 2: 'minecraft:cobblestone'},
2: {0: 'minecraft:block_of_raw_iron',
1: 'minecraft:diamond_block',
2: 'minecraft:gold_block'}}
我希望我的 txt 输出是
/fill 0 0 0 0 0 1 minecraft:diorite
/fill 0 0 2 0 0 2 minecraft:stone
/fill 1 0 0 1 0 1 minecraft:stone
/fill 1 0 2 1 0 2 minecraft:cobblestone
/fill 2 0 0 2 0 0 minecraft:block_of_raw_iron
/fill 2 0 1 2 0 1 minecraft:diamond_block
/fill 2 0 2 2 0 2 minecraft:gold_block
对于那些不知道 minecraft 命令语法的人：
/fill {x_start} {y_start} {z_start} {x_end} {y_end} {z_end} {block}
[开始，结束]（均包括在内），x 横向移动，z 向上或向下移动。
我几乎尝试了所有方法，但我几乎放弃了这段代码，所以我删除了我的进度，抱歉:(
有人可以帮忙吗？提前致谢。
编辑 1.：为了更好地测试，这里是火影忍者的像素艺术（前 5 行）
{0: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 1: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 2: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 3: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 4: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 5: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 6: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 7: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 8: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 9: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 10: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 11: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 12: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 13: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 14: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:block_of_raw_iron'}, 15: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:sand'}, 16: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 17: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 18: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 19: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:sand'}, 20: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:sand', 3: 'minecraft:block_of_gold', 4: 'minecraft:sponge'}, 21: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:diorite_slab', 4: 'minecraft:sand'}, 22: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 23: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:snow_block', 4: 'minecraft:diorite_slab'}, 24: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:sand', 4: 'minecraft:block_of_gold'}, 25: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:sand', 3: 'minecraft:sponge', 4: 'minecraft:sponge'}, 26: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:white_terracotta'}, 27: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 28: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:diorite_slab'}, 29: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:sand'}, 30: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:sponge'}, 31: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 32: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:snow_block'}, 33: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 34: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 35: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 36: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 37: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 38: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 39: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 40: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 41: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 42: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 43: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 44: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 45: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}}
和（我认为是）前 3 列的预期输出（再次假设玩家的位置 0、0、0）。
/fill 0 0 0 0 0 45 minecraft:diorite_slab
/fill 1 0 0 1 0 45 minecraft:diorite_slab
/fill 2 0 0 2 0 26 minecraft:diorite_slab
/fill 2 0 27 2 0 29 minecraft:mushroom_stem
/fill 2 0 30 2 0 45 minecraft:diorite_slab
我尝试基于 un-pivoting 将值矩阵写入坐标表示来编写解决方案，但压缩代码最终变得非常复杂，所以我放弃了它，并编写了一个基于而是嵌套循环，最终更容易编写。
基本上，这会循环遍历行，并且在每一行中，它将相同 material 的块分组，只要这些块是连续的。 （这就是 itertools.groupby() 的目的，它与 Pandas groupby 不同，因为 Pandas 版本 将 分组不连续的值一样。)
import pandas as pd
import itertools
from collections import namedtuple
FillCommand = namedtuple('FillCommand', 'minx minz maxx maxz blocks material')
def compress_row(j, s):
i = 0
for material, group in itertools.groupby(s):
num_elements = len(list(group))
maxz = i + num_elements - 1
yield FillCommand(
minx=j,
minz=i,
maxx=j,
maxz=maxz,
blocks=num_elements,
material=material,
)
i += num_elements
def compress_all(df):
height = len(df.index)
for j in range(height):
yield from compress_row(j, df.iloc[j])
def fill_to_string(fill_commands):
for cmd in fill_commands:
yield f"/fill {cmd.minx} 0 {cmd.minz} {cmd.maxx} 0 {cmd.maxz} {cmd.material}"
def convert_pic_to_fill(df):
return list(fill_to_string(compress_all(df)))
convert_pic_to_fill(df_naruto)
这是这段代码的输出：
/fill 0 0 0 0 0 45 minecraft:diorite_slab
/fill 1 0 0 1 0 45 minecraft:diorite_slab
/fill 2 0 0 2 0 19 minecraft:diorite_slab
/fill 2 0 20 2 0 20 minecraft:sand
/fill 2 0 21 2 0 24 minecraft:snow_block
/fill 2 0 25 2 0 25 minecraft:sand
/fill 2 0 26 2 0 45 minecraft:diorite_slab
/fill 3 0 0 3 0 15 minecraft:diorite_slab
/fill 3 0 16 3 0 18 minecraft:snow_block
/fill 3 0 19 3 0 19 minecraft:sand
/fill 3 0 20 3 0 20 minecraft:block_of_gold
/fill 3 0 21 3 0 21 minecraft:diorite_slab
/fill 3 0 22 3 0 23 minecraft:snow_block
/fill 3 0 24 3 0 24 minecraft:sand
/fill 3 0 25 3 0 25 minecraft:sponge
/fill 3 0 26 3 0 26 minecraft:sand
/fill 3 0 27 3 0 29 minecraft:snow_block
/fill 3 0 30 3 0 30 minecraft:sand
/fill 3 0 31 3 0 45 minecraft:diorite_slab
/fill 4 0 0 4 0 13 minecraft:diorite_slab
/fill 4 0 14 4 0 14 minecraft:block_of_raw_iron
/fill 4 0 15 4 0 15 minecraft:sand
/fill 4 0 16 4 0 18 minecraft:snow_block
/fill 4 0 19 4 0 19 minecraft:sand
/fill 4 0 20 4 0 20 minecraft:sponge
/fill 4 0 21 4 0 21 minecraft:sand
/fill 4 0 22 4 0 22 minecraft:snow_block
/fill 4 0 23 4 0 23 minecraft:diorite_slab
/fill 4 0 24 4 0 24 minecraft:block_of_gold
/fill 4 0 25 4 0 25 minecraft:sponge
/fill 4 0 26 4 0 26 minecraft:white_terracotta
/fill 4 0 27 4 0 27 minecraft:snow_block
/fill 4 0 28 4 0 28 minecraft:diorite_slab
/fill 4 0 29 4 0 29 minecraft:sand
/fill 4 0 30 4 0 30 minecraft:sponge
/fill 4 0 31 4 0 31 minecraft:diorite_slab
/fill 4 0 32 4 0 32 minecraft:snow_block
/fill 4 0 33 4 0 45 minecraft:diorite_slab
这是一个主要使用 shift 和 groupby 的解决方案：
def script(df):
z = (df != df.shift()).cumsum()
zri = z.reset_index()
ix_name = z.index.name
co_name = z.columns.name
for i in z:
v = zri.groupby(i)[ix_name].agg(['first', 'last'])
s = {co_name:i}
e = {co_name:i}
for _, r in v.iterrows():
s[ix_name] = r['first']
e[ix_name] = r['last']
material = df.loc[r['first'], i]
yield f'/fill {s["x"]} 0 {s["z"]} {e["x"]} 0 {e["z"]} {material}'
使用方法：
# df is the DataFrame of your dict
# label the axes
df = df.rename_axis(index='z', columns='x')
# select which axis to make major
a = list(script(df))
b = list(script(df.T))
res = min([a, b], key=len)
关于您的第一个示例数据：
>>> res
['/fill 0 0 0 0 0 1 minecraft:diorite',
'/fill 0 0 2 0 0 2 minecraft:stone',
'/fill 1 0 0 1 0 1 minecraft:stone',
'/fill 1 0 2 1 0 2 minecraft:cobblestone',
'/fill 2 0 0 2 0 0 minecraft:block_of_raw_iron',
'/fill 2 0 1 2 0 1 minecraft:diamond_block',
'/fill 2 0 2 2 0 2 minecraft:gold_block']
在您为“火影忍者的像素艺术”提供的前 5 行中：
>>> res
['/fill 0 0 0 45 0 0 minecraft:diorite_slab',
'/fill 0 0 1 45 0 1 minecraft:diorite_slab',
'/fill 0 0 2 19 0 2 minecraft:diorite_slab',
'/fill 20 0 2 20 0 2 minecraft:sand',
'/fill 21 0 2 24 0 2 minecraft:snow_block',
'/fill 25 0 2 25 0 2 minecraft:sand',
'/fill 26 0 2 45 0 2 minecraft:diorite_slab',
'/fill 0 0 3 15 0 3 minecraft:diorite_slab',
'/fill 16 0 3 18 0 3 minecraft:snow_block',
'/fill 19 0 3 19 0 3 minecraft:sand',
'/fill 20 0 3 20 0 3 minecraft:block_of_gold',
'/fill 21 0 3 21 0 3 minecraft:diorite_slab',
'/fill 22 0 3 23 0 3 minecraft:snow_block',
'/fill 24 0 3 24 0 3 minecraft:sand',
'/fill 25 0 3 25 0 3 minecraft:sponge',
'/fill 26 0 3 26 0 3 minecraft:sand',
'/fill 27 0 3 29 0 3 minecraft:snow_block',
'/fill 30 0 3 30 0 3 minecraft:sand',
'/fill 31 0 3 45 0 3 minecraft:diorite_slab',
'/fill 0 0 4 13 0 4 minecraft:diorite_slab',
'/fill 14 0 4 14 0 4 minecraft:block_of_raw_iron',
'/fill 15 0 4 15 0 4 minecraft:sand',
'/fill 16 0 4 18 0 4 minecraft:snow_block',
'/fill 19 0 4 19 0 4 minecraft:sand',
'/fill 20 0 4 20 0 4 minecraft:sponge',
'/fill 21 0 4 21 0 4 minecraft:sand',
'/fill 22 0 4 22 0 4 minecraft:snow_block',
'/fill 23 0 4 23 0 4 minecraft:diorite_slab',
'/fill 24 0 4 24 0 4 minecraft:block_of_gold',
'/fill 25 0 4 25 0 4 minecraft:sponge',
'/fill 26 0 4 26 0 4 minecraft:white_terracotta',
'/fill 27 0 4 27 0 4 minecraft:snow_block',
'/fill 28 0 4 28 0 4 minecraft:diorite_slab',
'/fill 29 0 4 29 0 4 minecraft:sand',
'/fill 30 0 4 30 0 4 minecraft:sponge',
'/fill 31 0 4 31 0 4 minecraft:diorite_slab',
'/fill 32 0 4 32 0 4 minecraft:snow_block',
'/fill 33 0 4 45 0 4 minecraft:diorite_slab']
附录: 使脚本相对于当前位置。
import numpy as np
def script(df, at=(0,0,0)):
z = (df != df.shift()).cumsum()
zri = z.reset_index()
ix_name = z.index.name
co_name = z.columns.name
for i in z:
v = zri.groupby(i)[ix_name].agg(['first', 'last'])
s = {co_name:i}
e = {co_name:i}
for _, r in v.iterrows():
s[ix_name] = r['first']
e[ix_name] = r['last']
material = df.loc[r['first'], i]
sp = np.array((s['x'], 0, s['z'])) + at
ep = np.array((e['x'], 0, e['z'])) + at
line = ' '.join(tuple(sp.astype(str)) + tuple(ep.astype(str)) + (material, ))
yield f'/fill {line}'
示例：
pos = (-5, 7, 3)
a = list(script(df, at=pos))
b = list(script(df.T, at=pos))
res = min([a, b], key=len)
>>> res
['/fill -5 7 3 -5 7 4 minecraft:diorite',
'/fill -5 7 5 -5 7 5 minecraft:stone',
'/fill -4 7 3 -4 7 4 minecraft:stone',
'/fill -4 7 5 -4 7 5 minecraft:cobblestone',
'/fill -3 7 3 -3 7 3 minecraft:block_of_raw_iron',
'/fill -3 7 4 -3 7 4 minecraft:diamond_block',
'/fill -3 7 5 -3 7 5 minecraft:gold_block']
我有 this code 本质上是将图像的像素转换为 minecraft 中的一个方块，它为您提供了一个“地图”，说明该方块的放置位置，以便在游戏中形成图像：代码生成一个 csv 文件，其中电子表格中的每个单元格对应一个块。
我想改进这一点，不仅输出 csv 文件，还输出一个 txt 文件，其中包含将在游戏中生成图像的 minecraft 命令。
此外，这些命令必须与玩家的 (x, y, z) 有相对位置，这应该通过元组或其他方式在代码中告知。
因此，假设玩家在游戏中位于 0, 0, 0，并且我的 csv 看起来像
这是用于测试的字典形式的相同数据框
{0: {0: 'minecraft:diorite', 1: 'minecraft:diorite', 2: 'minecraft:stone'},
1: {0: 'minecraft:stone', 1: 'minecraft:stone', 2: 'minecraft:cobblestone'},
2: {0: 'minecraft:block_of_raw_iron',
1: 'minecraft:diamond_block',
2: 'minecraft:gold_block'}}
我希望我的 txt 输出是
/fill 0 0 0 0 0 1 minecraft:diorite
/fill 0 0 2 0 0 2 minecraft:stone
/fill 1 0 0 1 0 1 minecraft:stone
/fill 1 0 2 1 0 2 minecraft:cobblestone
/fill 2 0 0 2 0 0 minecraft:block_of_raw_iron
/fill 2 0 1 2 0 1 minecraft:diamond_block
/fill 2 0 2 2 0 2 minecraft:gold_block
对于那些不知道 minecraft 命令语法的人：
/fill {x_start} {y_start} {z_start} {x_end} {y_end} {z_end} {block}
[开始，结束]（均包括在内），x 横向移动，z 向上或向下移动。
我几乎尝试了所有方法，但我几乎放弃了这段代码，所以我删除了我的进度，抱歉:(
有人可以帮忙吗？提前致谢。
编辑 1.：为了更好地测试，这里是火影忍者的像素艺术（前 5 行）
{0: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 1: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 2: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 3: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 4: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 5: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 6: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 7: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 8: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 9: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 10: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 11: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 12: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 13: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 14: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:block_of_raw_iron'}, 15: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:sand'}, 16: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 17: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 18: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 19: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:sand'}, 20: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:sand', 3: 'minecraft:block_of_gold', 4: 'minecraft:sponge'}, 21: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:diorite_slab', 4: 'minecraft:sand'}, 22: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 23: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:snow_block', 4: 'minecraft:diorite_slab'}, 24: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:snow_block', 3: 'minecraft:sand', 4: 'minecraft:block_of_gold'}, 25: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:sand', 3: 'minecraft:sponge', 4: 'minecraft:sponge'}, 26: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:white_terracotta'}, 27: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:snow_block'}, 28: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:diorite_slab'}, 29: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:snow_block', 4: 'minecraft:sand'}, 30: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:sand', 4: 'minecraft:sponge'}, 31: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 32: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:snow_block'}, 33: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 34: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 35: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 36: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 37: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 38: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 39: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 40: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 41: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 42: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 43: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 44: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}, 45: {0: 'minecraft:diorite_slab', 1: 'minecraft:diorite_slab', 2: 'minecraft:diorite_slab', 3: 'minecraft:diorite_slab', 4: 'minecraft:diorite_slab'}}
和（我认为是）前 3 列的预期输出（再次假设玩家的位置 0、0、0）。
/fill 0 0 0 0 0 45 minecraft:diorite_slab
/fill 1 0 0 1 0 45 minecraft:diorite_slab
/fill 2 0 0 2 0 26 minecraft:diorite_slab
/fill 2 0 27 2 0 29 minecraft:mushroom_stem
/fill 2 0 30 2 0 45 minecraft:diorite_slab
我尝试基于 un-pivoting 将值矩阵写入坐标表示来编写解决方案，但压缩代码最终变得非常复杂，所以我放弃了它，并编写了一个基于而是嵌套循环，最终更容易编写。
基本上，这会循环遍历行，并且在每一行中，它将相同 material 的块分组，只要这些块是连续的。 （这就是 itertools.groupby() 的目的，它与 Pandas groupby 不同，因为 Pandas 版本 将 分组不连续的值一样。)
import pandas as pd
import itertools
from collections import namedtuple
FillCommand = namedtuple('FillCommand', 'minx minz maxx maxz blocks material')
def compress_row(j, s):
i = 0
for material, group in itertools.groupby(s):
num_elements = len(list(group))
maxz = i + num_elements - 1
yield FillCommand(
minx=j,
minz=i,
maxx=j,
maxz=maxz,
blocks=num_elements,
material=material,
)
i += num_elements
def compress_all(df):
height = len(df.index)
for j in range(height):
yield from compress_row(j, df.iloc[j])
def fill_to_string(fill_commands):
for cmd in fill_commands:
yield f"/fill {cmd.minx} 0 {cmd.minz} {cmd.maxx} 0 {cmd.maxz} {cmd.material}"
def convert_pic_to_fill(df):
return list(fill_to_string(compress_all(df)))
convert_pic_to_fill(df_naruto)
这是这段代码的输出：
/fill 0 0 0 0 0 45 minecraft:diorite_slab
/fill 1 0 0 1 0 45 minecraft:diorite_slab
/fill 2 0 0 2 0 19 minecraft:diorite_slab
/fill 2 0 20 2 0 20 minecraft:sand
/fill 2 0 21 2 0 24 minecraft:snow_block
/fill 2 0 25 2 0 25 minecraft:sand
/fill 2 0 26 2 0 45 minecraft:diorite_slab
/fill 3 0 0 3 0 15 minecraft:diorite_slab
/fill 3 0 16 3 0 18 minecraft:snow_block
/fill 3 0 19 3 0 19 minecraft:sand
/fill 3 0 20 3 0 20 minecraft:block_of_gold
/fill 3 0 21 3 0 21 minecraft:diorite_slab
/fill 3 0 22 3 0 23 minecraft:snow_block
/fill 3 0 24 3 0 24 minecraft:sand
/fill 3 0 25 3 0 25 minecraft:sponge
/fill 3 0 26 3 0 26 minecraft:sand
/fill 3 0 27 3 0 29 minecraft:snow_block
/fill 3 0 30 3 0 30 minecraft:sand
/fill 3 0 31 3 0 45 minecraft:diorite_slab
/fill 4 0 0 4 0 13 minecraft:diorite_slab
/fill 4 0 14 4 0 14 minecraft:block_of_raw_iron
/fill 4 0 15 4 0 15 minecraft:sand
/fill 4 0 16 4 0 18 minecraft:snow_block
/fill 4 0 19 4 0 19 minecraft:sand
/fill 4 0 20 4 0 20 minecraft:sponge
/fill 4 0 21 4 0 21 minecraft:sand
/fill 4 0 22 4 0 22 minecraft:snow_block
/fill 4 0 23 4 0 23 minecraft:diorite_slab
/fill 4 0 24 4 0 24 minecraft:block_of_gold
/fill 4 0 25 4 0 25 minecraft:sponge
/fill 4 0 26 4 0 26 minecraft:white_terracotta
/fill 4 0 27 4 0 27 minecraft:snow_block
/fill 4 0 28 4 0 28 minecraft:diorite_slab
/fill 4 0 29 4 0 29 minecraft:sand
/fill 4 0 30 4 0 30 minecraft:sponge
/fill 4 0 31 4 0 31 minecraft:diorite_slab
/fill 4 0 32 4 0 32 minecraft:snow_block
/fill 4 0 33 4 0 45 minecraft:diorite_slab
这是一个主要使用 shift 和 groupby 的解决方案：
def script(df):
z = (df != df.shift()).cumsum()
zri = z.reset_index()
ix_name = z.index.name
co_name = z.columns.name
for i in z:
v = zri.groupby(i)[ix_name].agg(['first', 'last'])
s = {co_name:i}
e = {co_name:i}
for _, r in v.iterrows():
s[ix_name] = r['first']
e[ix_name] = r['last']
material = df.loc[r['first'], i]
yield f'/fill {s["x"]} 0 {s["z"]} {e["x"]} 0 {e["z"]} {material}'
使用方法：
# df is the DataFrame of your dict
# label the axes
df = df.rename_axis(index='z', columns='x')
# select which axis to make major
a = list(script(df))
b = list(script(df.T))
res = min([a, b], key=len)
关于您的第一个示例数据：
>>> res
['/fill 0 0 0 0 0 1 minecraft:diorite',
'/fill 0 0 2 0 0 2 minecraft:stone',
'/fill 1 0 0 1 0 1 minecraft:stone',
'/fill 1 0 2 1 0 2 minecraft:cobblestone',
'/fill 2 0 0 2 0 0 minecraft:block_of_raw_iron',
'/fill 2 0 1 2 0 1 minecraft:diamond_block',
'/fill 2 0 2 2 0 2 minecraft:gold_block']
在您为“火影忍者的像素艺术”提供的前 5 行中：
>>> res
['/fill 0 0 0 45 0 0 minecraft:diorite_slab',
'/fill 0 0 1 45 0 1 minecraft:diorite_slab',
'/fill 0 0 2 19 0 2 minecraft:diorite_slab',
'/fill 20 0 2 20 0 2 minecraft:sand',
'/fill 21 0 2 24 0 2 minecraft:snow_block',
'/fill 25 0 2 25 0 2 minecraft:sand',
'/fill 26 0 2 45 0 2 minecraft:diorite_slab',
'/fill 0 0 3 15 0 3 minecraft:diorite_slab',
'/fill 16 0 3 18 0 3 minecraft:snow_block',
'/fill 19 0 3 19 0 3 minecraft:sand',
'/fill 20 0 3 20 0 3 minecraft:block_of_gold',
'/fill 21 0 3 21 0 3 minecraft:diorite_slab',
'/fill 22 0 3 23 0 3 minecraft:snow_block',
'/fill 24 0 3 24 0 3 minecraft:sand',
'/fill 25 0 3 25 0 3 minecraft:sponge',
'/fill 26 0 3 26 0 3 minecraft:sand',
'/fill 27 0 3 29 0 3 minecraft:snow_block',
'/fill 30 0 3 30 0 3 minecraft:sand',
'/fill 31 0 3 45 0 3 minecraft:diorite_slab',
'/fill 0 0 4 13 0 4 minecraft:diorite_slab',
'/fill 14 0 4 14 0 4 minecraft:block_of_raw_iron',
'/fill 15 0 4 15 0 4 minecraft:sand',
'/fill 16 0 4 18 0 4 minecraft:snow_block',
'/fill 19 0 4 19 0 4 minecraft:sand',
'/fill 20 0 4 20 0 4 minecraft:sponge',
'/fill 21 0 4 21 0 4 minecraft:sand',
'/fill 22 0 4 22 0 4 minecraft:snow_block',
'/fill 23 0 4 23 0 4 minecraft:diorite_slab',
'/fill 24 0 4 24 0 4 minecraft:block_of_gold',
'/fill 25 0 4 25 0 4 minecraft:sponge',
'/fill 26 0 4 26 0 4 minecraft:white_terracotta',
'/fill 27 0 4 27 0 4 minecraft:snow_block',
'/fill 28 0 4 28 0 4 minecraft:diorite_slab',
'/fill 29 0 4 29 0 4 minecraft:sand',
'/fill 30 0 4 30 0 4 minecraft:sponge',
'/fill 31 0 4 31 0 4 minecraft:diorite_slab',
'/fill 32 0 4 32 0 4 minecraft:snow_block',
'/fill 33 0 4 45 0 4 minecraft:diorite_slab']
附录: 使脚本相对于当前位置。
import numpy as np
def script(df, at=(0,0,0)):
z = (df != df.shift()).cumsum()
zri = z.reset_index()
ix_name = z.index.name
co_name = z.columns.name
for i in z:
v = zri.groupby(i)[ix_name].agg(['first', 'last'])
s = {co_name:i}
e = {co_name:i}
for _, r in v.iterrows():
s[ix_name] = r['first']
e[ix_name] = r['last']
material = df.loc[r['first'], i]
sp = np.array((s['x'], 0, s['z'])) + at
ep = np.array((e['x'], 0, e['z'])) + at
line = ' '.join(tuple(sp.astype(str)) + tuple(ep.astype(str)) + (material, ))
yield f'/fill {line}'
示例：
pos = (-5, 7, 3)
a = list(script(df, at=pos))
b = list(script(df.T, at=pos))
res = min([a, b], key=len)
>>> res
['/fill -5 7 3 -5 7 4 minecraft:diorite',
'/fill -5 7 5 -5 7 5 minecraft:stone',
'/fill -4 7 3 -4 7 4 minecraft:stone',
'/fill -4 7 5 -4 7 5 minecraft:cobblestone',
'/fill -3 7 3 -3 7 3 minecraft:block_of_raw_iron',
'/fill -3 7 4 -3 7 4 minecraft:diamond_block',
'/fill -3 7 5 -3 7 5 minecraft:gold_block']