如何结合 Flux 和 Mono
How to combine Flux and Mono
假设我们有以下函数
fun getAnnualData(tenant: String): Flux<DashboardResponse> {
val year = LocalDate.now().year
val annualExpenses = expenseFinder.sumAllByYearAndTenant(year = year, tenant = tenant)
val warehouseExpenses = expenseFinder.sumWarehouseByYearAndTenant(year = year, tenant = tenant)
val annualRevenues = revenueFinder.sumAllByYearAndTenant(year = year, tenant = tenant)
return annualExpenses.zipWith(annualRevenues)
.filter { it.t1._id?.year == year }
.filter { it.t2._id?.year == year }
.map {
DashboardResponse(
period = Period.ANNUAL,
expenses = it.t1,
revenue = it.t2
)
}
}
并且我想将 warehouseExpenses
添加到返回值中。我该怎么做?
在哪里
- 年度费用 = 通量
- 仓库费用 = Mono
- 年收入 = 通量
您可以简单地使用 flatMap
来组合 Mono:
Flux.just(...).zipWith(Flux.just(...))
.filter(...)
.flatMap(tuple -> Mono.just(true).map(m -> new DashboardResponse(tuple.getT1(), tuple.getT2(), m)));
假设我们有以下函数
fun getAnnualData(tenant: String): Flux<DashboardResponse> {
val year = LocalDate.now().year
val annualExpenses = expenseFinder.sumAllByYearAndTenant(year = year, tenant = tenant)
val warehouseExpenses = expenseFinder.sumWarehouseByYearAndTenant(year = year, tenant = tenant)
val annualRevenues = revenueFinder.sumAllByYearAndTenant(year = year, tenant = tenant)
return annualExpenses.zipWith(annualRevenues)
.filter { it.t1._id?.year == year }
.filter { it.t2._id?.year == year }
.map {
DashboardResponse(
period = Period.ANNUAL,
expenses = it.t1,
revenue = it.t2
)
}
}
并且我想将 warehouseExpenses
添加到返回值中。我该怎么做?
在哪里
- 年度费用 = 通量
- 仓库费用 = Mono
- 年收入 = 通量
您可以简单地使用 flatMap
来组合 Mono:
Flux.just(...).zipWith(Flux.just(...))
.filter(...)
.flatMap(tuple -> Mono.just(true).map(m -> new DashboardResponse(tuple.getT1(), tuple.getT2(), m)));