字典和输入：如果 `input` 包含我想要打印值的任何键

Question

我正在尝试构建一种简单的聊天机器人，但是当 input 不在字典中时，else 块正常工作...

我想打印 value，即使 input 是来自 keys 和其他一些词。例如：

发短信：你好回答：你好

所以，如果 input 包含我想要打印值的任何键。

如果你知道怎么做，请告诉我。谢谢。

words = {"good night": ["nighty night", "good night", "sleep well"],
         "good morning": ["good morning", "wakey-wakey!", "rise and shine!"],
         "hi": ["hello", "hey", "hola"]
         }


text_punk = input("text something: ")

if text_punk in words:
    punk = random.choice(words[text_punk])

    print(punk)
    talk(punk) #this is for pyttsx3
else:
    print("problem!")

Answer 1

您可以执行以下操作。

import random
words = {"good night": ["nighty night", "good night", "sleep well"],
         "good morning": ["good morning", "wakey-wakey!", "rise and shine!"],
         "hi": ["hello", "hey", "hola"]
         }

text_punk = input("text something: ")

greet_words = words.keys() #check if your key words is in input_text.
word_available = [word for word in greet_words if word in text_punk]

if word_available: # if words are available take the first of key.
    punk = random.choice(words[word_available[0]])

    print(punk)
    talk(punk) #this is for pyttsx3
else:
    print("problem!")

Answer 2

检查给定的文本是否是字典只会在准确的文本在字典中时给出结果，所以如果您检查 "hi" in words 它会起作用，因为 "hi" 是字典，这不适用于 "hi there" 的部分检查，因为你需要检查字典中的任何键是否存在于输入文本中，所以像

text_punk = input("text something: ")
for msj,replies in words.items():#with items we get both the key and its value in one go
    if msj in text_punk:
        punk = random.choice(replies)
        print(punk)
        break #with this we stop the loop at the first match

字典和输入：如果 `input` 包含我想要打印值的任何键

Dictionary and Input: if the `input` contains any of the keys I want to print the value

python

dictionary

input

chatbot