无法将模拟容器设为 return 除了 null

Question

我有一个测试失败了，因为我无法成功地存根控制器的 get 方法：

1) Tests\my-project\BackendBundle\Service\PdfGenerateServiceTest::test_getHttpPathToPtImage_should_return_the_default_avatar_when_photo_is_null
TypeError: Argument 1 passed to Mock_Pdf_d0288d34::setLogger() must implement interface Psr\Log\LoggerInterface, null given, called in /var/www/my-project/src/my-project/BackendBundle/Service/PdfGenerateService.php on line 66

测试

    public function test_getHttpPathToPtImage_should_return_the_default_avatar_when_photo_is_null()
    {
        $protocolAndHost = "http://foo.bar.com";
        $service = new PdfGenerateService($this->createFileServiceMock(), $this->createTranslatorMock(), $this->createSnappyMock(), $this->createContainerMock(), $protocolAndHost);
        $httpPathToPtImage = $service->getHttpPathToPtImage(null);

        self::assertEquals($httpPathToPtImage, $protocolAndHost . "abc/def");
    }

失败的构造函数

    public function __construct(FileService $fileService, Translator $translator, Pdf $snappy, ContainerInterface $container, string $protocolAndHost)
    {
        $this->fileService = $fileService;
        $this->translator = $translator;
        $this->currentLocale = $this->translator->getLocale();

        /* Could reconfigure the service using `service.yml` to pass these in using DI */
        $this->twig = $container->get('twig');
        $this->logger = $container->get('logger');  // <--- should not be null

        $timeoutInSeconds = 15; // can be high, since the job is done async in a job (user does not wait)
        $snappy->setLogger($this->logger); // <--- THIS FAILS due to $this->logger being null

存根

    protected function createContainerMock()
    {
        $containerMock = $this->createMock('Symfony\Component\DependencyInjection\ContainerInterface');
        $loggerMock = $this->createLoggerMock();
        $containerMock->method('get')->will($this->returnValueMap([
            ['logger', $loggerMock]
        ]));
        return $containerMock;
    }

我真的不明白为什么 get('logger') 只调用 returns null 当我设置了一个要使用上面的 returnValueMap 调用返回的模拟时。

我偶然发现了一个关于这个主题的 SO 问题，其中 someone mentioned 您需要提供所有参数，甚至是可选参数。然后我检查了界面，它确实列出了第二个参数：

public function get($id, $invalidBehavior = self::EXCEPTION_ON_INVALID_REFERENCE);

仍然，将地图更改为 ['logger', null, $loggerMock] 没有任何变化，所以我对接下来要尝试什么感到有点不知所措。

PHPunit 6.5，PHP7.2，Symfony 3.4

Answer 1

您真的很接近解决方案。为 returnValueMap 中的可选参数提供值时，您必须使用该值本身，而不仅仅是 null。

所以不用

['logger', null, $loggerMock]

尝试指定

['logger', ContainerInterface::EXCEPTION_ON_INVALID_REFERENCE, $loggerMock]

完整的调用如下所示：

$containerMock->method('get')->will($this->returnValueMap([
   ['logger', ContainerInterface::EXCEPTION_ON_INVALID_REFERENCE, $loggerMock]
]));

无法将模拟容器设为 return 除了 null

Unable to get mock container to return anything but null

phpunit

symfony

symfony-3.4