如何在 golang 中根据文件名正则表达式查找具有所有扩展名的文件

How to find thee files with all extension based on file name regex in golang

下面的代码可以打开名称为 rx80_AWS.png 的文件,但我想打开名称为 rx80_AWS* 的文件,而不管扩展名是什么,因为文件名是唯一的,但我们上传 .png .pdf 和 .您文件夹中的 jpeg 文件

func DownloadCert(w http.ResponseWriter, r *http.Request) {
    Openfile, err := os.Open("./certificate/rx80_AWS.png") //Open the file to be downloaded later
    defer Openfile.Close()                                 //Close after function return
    fmt.Println("FIle:", files)
    if err != nil {
        http.Error(w, "File not found.", 404) //return 404 if file is not found
        return
    }

    tempBuffer := make([]byte, 512)                       //Create a byte array to read the file later
    Openfile.Read(tempBuffer)                             //Read the file into  byte
    FileContentType := http.DetectContentType(tempBuffer) //Get file header

    FileStat, _ := Openfile.Stat()                     //Get info from file
    FileSize := strconv.FormatInt(FileStat.Size(), 10) //Get file size as a string

    Filename := attuid + "_" + skill

    //Set the headers
    w.Header().Set("Content-Type", FileContentType+";"+Filename)
    w.Header().Set("Content-Length", FileSize)

    Openfile.Seek(0, 0)  //We read 512 bytes from the file already so we reset the offset back to 0
    io.Copy(w, Openfile) //'Copy' the file to the client

}

使用filepath.Glob.

files, err := filepath.Glob("certificate/rx80_AWS*")
if err != nil {
   // handle errors
}
for _, filename in files {
   //...handle each file...
}

Here is an example that works with the playground 通过匹配 /bin/*cat(匹配 catzcat 等)。