Bash 对 Map 的值进行降序排序

Question

我在 bash 中声明了一个地图，如下所示

declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)

我想在具有分隔符 (:) 的 Key 中拆分字符串，并按值的降序顺序获取输出，如下所示

P - Q - R - S - 2346957.02    
E - F - G - H - 113770.0    
W - X - Y - Z - 53831.93    
A - B - C - D - 813.0

我正在尝试的代码如下

for k in "${!myMap[@]}"    
do    
  arrIN=(${k//:/ })    
  echo ${arrIN[0]} ' - ' ${arrIN[1]} ' - ' ${arrIN[2]} ' - ' ${arrIN[3]} ' - ' ${myMap["$k"]}    
done | sort ${myMap["$k"]}

但是使用我的代码的输出是这样的

E - F - G - H - 113770.0    
W - X - Y - Z - 53831.93    
P - Q - R - S - 2346957.02    
A - B - C - D - 813.0

有没有简单的方法可以做到这一点？

Answer 1

如果打印原始键和值，则按第二列排序 (k2)，numeric reverse.

#! /bin/bash
declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)

for k in ${!myMap[@]} ; do
    echo $k ${myMap[$k]}
done | sort -rnk2 | sed 's/[: ]/ - /g'

如果拆分key，需要按第九列排序：

for k in "${!myMap[@]}" ; do    
    arrIN=(${k//:/ })
    echo ${arrIN[0]} - ${arrIN[1]} - ${arrIN[2]} - ${arrIN[3]} - ${myMap[$k]}
done | sort -nrk9

Answer 2

使用文件名通配符对键进行排序的替代方法。

#!/usr/bin/env bash

declare -A myMap
myMap=( [A:B:C:D]=813.0 [P:Q:R:S]=2346957.02 [W:X:Y:Z]=53831.93 [E:F:G:H]=113770.0)

tmpDir=
trap 'rm -fr "$tmpDir"' EXIT INT
tmpDir=$(mktemp -d)

myKeys=("${!myMap[@]}")

# Create a file per key in the temp directory
touch "${myKeys[@]/#/$tmpDir/}"

# Load keys from temp directory benefiting from auto sorting
myKeys=("$tmpDir/"*)

# Strip file path from keys
myKeys=("${myKeys[@]##*/}")

# Iterate keys in reverse order
for (( i=${#myKeys[@]}-1; i>=0; i-- )); do

  k=${myKeys[i]}

  # Split key by :
  IFS=: read -ra ka <<<"$k"

  # Get corresponding value
  v=${myMap[$k]}

  # Print joined key elements with " - " followed by value
  printf '%s%s%s%s%s\n' "${ka[@]/%/ - }" "$v"
done

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