IllegalArgumentException 会终止应用程序吗？

Question

以下代码来自官方示例project.

当 Result.Error(IllegalArgumentException("City doesn't exist")) 启动时，IllegalArgumentException 会终止应用程序吗？

sealed class Result<out R> {
    data class Success<out T>(val data: T) : Result<T>()
    data class Error(val exception: Exception) : Result<Nothing>()
}


class DetailsViewModel @Inject constructor(
    private val destinationsRepository: DestinationsRepository,
    savedStateHandle: SavedStateHandle
) : ViewModel() {

    private val cityName = savedStateHandle.get<String>(KEY_ARG_DETAILS_CITY_NAME)!!

    val cityDetails: Result<ExploreModel>
        get() {
            val destination = destinationsRepository.getDestination(cityName)
            return if (destination != null) {
                Result.Success(destination)
            } else {
                Result.Error(IllegalArgumentException("City doesn't exist")) // Will IllegalArgumentException termination an app ?
            }
        }
}

Answer 1

在这种情况下，应用程序不会崩溃（终止），因为 IllegalArgumentException 异常只是被创建，而不是被抛出。如果抛出异常并且未被 try-catch 运算符捕获，应用程序将崩溃（终止），如下所示：

throw IllegalArgumentException("City doesn't exist")

IllegalArgumentException 会终止应用程序吗？

Will IllegalArgumentException termination an app?

android

terminate

illegalargumentexception

kotlin

android-studio