Pivot 的 PLSQL 结果 Table

Question

我想在 PLSQL 中运行查询以获取过去六个月内数据table中的销售数量总和，并将其按月分配给列。

到目前为止，我将这段代码 select 我想要的数据

SELECT 
  * 
FROM 
  (
    select 
      CATALOG_NO as PartNo, 
      to_char(INVOICE_DATE, 'MM') as tday, 
      sum(INVOICED_QTY) as qty 
    from 
      db.INV_ITEM_JOIN 
    WHERE 
      upper(CATALOG_GROUP) = upper('SPAM') 
      AND INVOICE_DATE between add_months(
        trunc(sysdate, 'mm'), 
        -6
      ) 
      and last_day(
        add_months(
          trunc(sysdate, 'mm'), 
          -1
        )
      ) 
    group by 
      to_char(INVOICE_DATE, 'MM'), 
      CATALOG_NO 
    order by 
      CATALOG_NO
  )

然后我得到了结果，为了创建 PIVOT，我在 select 查询

之后添加了这段代码

PIVOT (
  SUM(qty) FOR TDAY IN (
    01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 
    12
  )
)

所以一旦我添加它 returns table as PartNo, 01,02,03,04,05,06,07,08,09,10,11,12 像个聪明人。

但是数据只去了101112个月而已，其他的没有填。我能得到解决这个问题的帮助吗？

Answer 1

TO_CHAR(INVOICE_DATE, 'MM') 输出一个零填充的两位数字符串，因此您要么想使用：

PIVOT (
  SUM(qty) FOR TDAY IN (
    '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12'
  )
)

或者，使用 EXTRACT(MONTH FROM invoice_date) 而不是 TO_CHAR 然后你可以使用数值：

SELECT * 
FROM   (
  select CATALOG_NO as PartNo, 
         EXTRACT(MONTH FROM INVOICE_DATE) as tday, 
         sum(INVOICED_QTY) as qty 
  from   db.INV_ITEM_JOIN 
  WHERE  upper(CATALOG_GROUP) = 'SPAM'
  AND    INVOICE_DATE >= add_months(trunc(sysdate, 'mm'), -6) 
  AND    INVOICE_DATE <  trunc(sysdate, 'mm')
  GROUP BY 
         EXTRACT(MONTH FROM INVOICE_DATE), 
         CATALOG_NO 
  order by 
         CATALOG_NO
)
PIVOT (
  SUM(qty) FOR TDAY IN (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)
)

顺便说一句：

INVOICE_DATE between add_months(trunc(sysdate, 'mm'), -6) 
                 and last_day(add_months(trunc(sysdate, 'mm'), -1))

将排除上个月最后一天时间从 00:00:01 到 23:59:59 的值。如果您想包括整个范围，请使用：

AND    INVOICE_DATE >= add_months(trunc(sysdate, 'mm'), -6) 
AND    INVOICE_DATE <  trunc(sysdate, 'mm')

db<>fiddle here

Pivot 的 PLSQL 结果 Table

PLSQL results to Pivot Table

sql

oracle

pivot