Python 列表理解或 lambda 可能适用于我给定的代码片段？

Question

编辑：删除了未定义的变量。所以我的代码基本上是，尝试比较一个列表的值是否存在于另一个列表中。如果是这样，将该值附加到第三个列表。如果该值不存在，则附加到第 4 个列表。执行此任务最有效和可读的方法是什么。我的代码示例：

a = [1,2,3]
b = [2,3,4,5,6,7]
c = []
d = []
for ele in a:
    if ele in b:
        c.append(ele )
    else:
        d.append(ele)

Answer 1

解决这个问题的最佳方法是使用集合。

import random
a = [random.randint(1, 15) for _ in range(5)]
b = [random.randint(1, 15) for _ in range(7)]

print(a)
print(b)

set_a = set(a)
set_b = set(b)
set_intersection = set_a.intersection(set_b)
set_diff = set_a.difference(set_b)

print(list(set_intersection))
print(list(set_diff))

Answer 2

c = [i for i in a if i in b]

d = [i for i in a if i not in b]

Answer 3

a=[2,3,4,5]
b=[3,5,7,9]

c = [value for value in a if value in b] 
d = [value for value in a if value not in b]

print(f'Present in B: {c}')
print(f"Not present in B: {d}")

Python 列表理解或 lambda 可能适用于我给定的代码片段？

Python list comprehension or lambda possible for my given code snippet?

python

lambda

list-comprehension