如何 select 双情节饼图例中只有一个情节？

Question

我创造了两个甜甜圈形状的 plt.pie。第一个包含第二个，第二个包含空洞，一个白洞。我想创建一个 plt.legend () 但只包括第二个情节。我似乎不能 select 只有第二个。

在我的标题中，我想显示 labels_origin 的每个标签及其代表的百分比，以及正确的颜色代码。

看来他是在混合我的2个地块的颜色。

有人有解决办法吗？

import matplotlib.pyplot as plt

labels = ["Part pertes", "Part humaine", "Part animale", "Part autres utilisations", "Part semences", "Part traitements"]
sizes = [part_pertes , part_humaine , part_animale, part_autres_util, part_semences, part_traitements]

labels_origine = ["Part pertes - Animale", "Part pertes - Végétale",
                  "Part humaine - Animale", "Part humaine - Végétale",
                  "Part animale - Animale", "Part animale - Végétale",
                  "Part autres utilisations - Animale", "Part autres utilisations - Végétale",
                  "Part semences - Animale", "Part semences - Végétale",
                  "Part traitements - Animale", "Part traitements - Végétale"]
sizes_origine = [part_pertes_prod_anim, part_pertes_prod_veget,
                 part_humaine_prod_anim , part_humaine_prod_veget,
                 part_animale_prod_anim, part_animale_prod_veget,
                 part_autres_util_prod_anim,  part_autres_util_prod_veget,
                 part_semences_prod_anim, part_semences_prod_veget,
                 part_traitements_prod_anim,  part_traitements_prod_veget]

size = 0.3
fig, ax = plt.subplots(figsize=(10, 10))

# Couleurs
colors = ["#ff5959", "#2693ff", "#59FF59", "#FF8C19", "#3D3DC8", "#ffb3e6"]
colors_origine = ['#ff9999', "#ffd8d8", "#66b3ff", "#a5d2ff", "#99ff99", "#D8FFD8",
                  "#FFAC59", "#FFCB98", "#c2c2f0", "#7B7BDC", "#ffb3e6", "#FFF2FA" ]

#Plot
plot1 = plt.pie(sizes, labels=labels, colors=colors, autopct='%1.1f%%', startangle=45, pctdistance=0.85,
        textprops={"fontsize":14}, radius=1, wedgeprops=dict(width=size, edgecolor='w'))

plot2 = plt.pie(sizes_origine, colors=colors_origine, startangle=45, pctdistance=0.85,
        radius=1-size, wedgeprops=dict(width=size, edgecolor='w'))

plt.axis('equal')
plt.tight_layout()

total=sum(sizes_origine)

plt.legend(loc=0,
    labels=['%s, %1.1f%%' % (
        l, (float(s) / total) * 100) for l, s in zip(labels_origine, sizes_origine)],
    bbox_to_anchor=(1.7, 1),
    prop={'size': 14},
    title="Origine des parts",
    title_fontsize=16)

plt.title("Répartition des différentes parts de la disponibilité intérieure mondiale", fontsize=20)
plt.show()

Screenshot of my double plot pie

Answer 1

快速解决方法是手动设置图例句柄颜色。您需要使用 .gca() 获取当前轴，然后从轴中获取图例并通过遍历它们手动设置颜色（需要在图例调用后插入代码）：

ax = plt.gca()
leg = ax.get_legend()
for index, color_origine in enumerate(colors_origine):
    leg.legendHandles[index].set_color(color_origine)

具有随机值的工作示例：

import matplotlib.pyplot as plt

labels = ["Part pertes", "Part humaine", "Part animale", "Part autres utilisations", "Part semences", "Part traitements"]
sizes = [15 , 38 , 200, 10, 25, 44]

labels_origine = ["Part pertes - Animale", "Part pertes - Végétale",
                  "Part humaine - Animale", "Part humaine - Végétale",
                  "Part animale - Animale", "Part animale - Végétale",
                  "Part autres utilisations - Animale", "Part autres utilisations - Végétale",
                  "Part semences - Animale", "Part semences - Végétale",
                  "Part traitements - Animale", "Part traitements - Végétale"]
sizes_origine = [11, 45,
                 100 , 12,
                 24, 3,
                 55,  87,
                 34, 43,
                 22,  77]

size = 0.3
fig= plt.figure(figsize=(10, 10))


# Couleurs
colors = ["#ff5959", "#2693ff", "#59FF59", "#FF8C19", "#3D3DC8", "#ffb3e6"]
colors_origine = ['#ff9999', "#ffd8d8", "#66b3ff", "#a5d2ff", "#99ff99", "#D8FFD8",
                  "#FFAC59", "#FFCB98", "#c2c2f0", "#7B7BDC", "#ffb3e6", "#FFF2FA" ]

#Plot
plot1 = plt.pie(sizes, labels=labels, colors=colors, autopct='%1.1f%%', startangle=45, pctdistance=0.85,
        textprops={"fontsize":14}, radius=1, wedgeprops=dict(width=size, edgecolor='w'))

plot2 = plt.pie(sizes_origine, colors=colors_origine, startangle=45, pctdistance=0.85,
        radius=1-size, wedgeprops=dict(width=size, edgecolor='w'))

plt.axis('equal')
plt.tight_layout()

total=sum(sizes_origine)

plt.legend(loc=0,
    labels=['%s, %1.1f%%' % (
        l, (float(s) / total) * 100) for l, s in zip(labels_origine, sizes_origine)],
    bbox_to_anchor=(1.7, 1),
    prop={'size': 14},
    title="Origine des parts",
    title_fontsize=16)

plt.title("Répartition des différentes parts de la disponibilité intérieure mondiale", fontsize=20)

# THIS ↓↓↓↓↓
ax = plt.gca()
leg = ax.get_legend()
for index, color_origine in enumerate(colors_origine):
    leg.legendHandles[index].set_color(color_origine)

plt.show()

输出：

如何 select 双情节饼图例中只有一个情节？

How to select only one plot in a legend of a double plot pie?

python

matplotlib

pie-chart