如何在 shell 脚本中逐行比较一个文件的内容与另一个文件的内容?

How to compare content of one file to the another file in shell script line by line?

文件 1 内容(TOp.txt):

/
/boot
/home
/ptd
/ptd/tcd
/ptd/splunkforwarderdd
/ptd/sdt/pqr
/ptd/smr
/ptd/apps/ddas

文件 2 内容(POp.txt):

/
/boot
/home
/ptd
/ptd/tcd
/ptd/apps/ddas
/ptc/ddd

输出文件 1(Op1.txt):

/ptd/splunkforwarderdd
/ptd/sdt/pqr
/ptd/smr

输出文件 2(Op2.txt):

/ptc/ddd

Shell 脚本:

while read linesT; do
    TOp=$linesT
      while read linesP; do
         POp=$linesp
         if [[ "$TOp" == "$POp"  ]]; then        
         a=cool
         else 
         echo $TOp
         fi
     done < POp.txt
  done < TOp.txt

我试过上面的代码。但它没有按预期工作。

我想要 TOp.txt 文件将每一行与 POp.txt 文件中的每一行进行比较,并将文件 TOp.txt 中缺少的行显示为输出。

POp.txt 文件相同。

你应该用不同的fd单次阅读。不过sort/diff会好很多

while read -u 3 linesT && read -u 4 linesP; do
  TOp=$linesT
  POp=$linesp
  if [[ "$TOp" == "$POp"  ]]; then
     a=cool
     else
     echo $TOp
  fi
done 3< TOp.txt 4< POp.txt

假设两个文件的#lines 相同,请您尝试以下操作:

#!/bin/bash

while IFS=$'\t' read -r top pop; do
    if [[ $top != $pop ]]; then
        echo "$top" >> Op1.txt
        echo "$pop" >> Op2.txt
    fi
done < <(paste <(sort TOp.txt) <(sort POp.txt))

paste ...命令并排合并两个排序的文件 然后将变量 $top$pop 分配给每一行。

[编辑]
如果两个文件的行不平衡,用awk解决方法会更好:

awk 'NR==FNR {t[[=11=]]++; next}                                    # memorize lines in "TOp.txt"
    {p[[=11=]]++}                                                   # memorize lines in "POp.txt"
    END {
        for (i in t) if (p[i] == "") print i > "Op1.txt"        # lines only in "TOp.txt"
        for (i in p) if (t[i] == "") print i > "Op2.txt"        # lines only in "POp.txt"
    }
' TOp.txt POp.txt

comm比较文件行数

有趣的选项:

   -1     suppress column 1 (lines unique to FILE1)

   -2     suppress column 2 (lines unique to FILE2)

   -3     suppress column 3 (lines that appear in both files)

   --nocheck-order
          do not check that the input is correctly sorted

答案:

comm --nocheck-order -23 TOp.txt POp.txt > Op1.txt
comm --nocheck-order -13 TOp.txt POp.txt > Op2.txt

对于未排序的文件,您可能会得到错误的结果,所以这样做:

$ comm -23 <(sort TOp.txt) <(sort POp.txt)
/ptd/sdt/pqr
/ptd/smr
/ptd/splunkforwarderdd

$ comm -13 <(sort TOp.txt) <(sort POp.txt)
/ptc/ddd

抱歉,我没有完全理解您的算法。它似乎表现得像 最近邻域采样,但变量的使用 diff 我觉得很晦涩。

处理图像的常用方法是存储整个像素 一开始进入内存。 然后你可以随机访问下面的任何像素 过程和代码会更直接。

顺便说一句,您发布的输入图像太小,无法识别问题,因为 非常细的线条和小点很容易通过过滤甚至折叠 如果算法合适。 会推荐使用大图来评价。

这是我根据你的代码重写的:

#include <stdio.h>
#include <stdlib.h>

#include "bmp.h"

int main(int argc, char *argv[])
{
    // ensure proper usage
    if (argc != 4) {
        fprintf(stderr, "Usage: resize n infile outfile\n");
        return 1;
    }

    // read the scaling factor
    float f = atof(argv[1]);
    if(f <= 0 || f > 1) {
        fprintf(stderr, "f, the resize factor, must be between 0 and 1.\n");
        return 1;
    }
    char *infile = argv[2];
    char *outfile = argv[3];

    // open input file
    FILE *inptr = fopen(infile, "r");
    if (inptr == NULL) {
        fprintf(stderr, "Could not open %s.\n", infile);
        return 2;
    }

    // open output file
    FILE *outptr = fopen(outfile, "w");
    if (outptr == NULL) {
        fclose(inptr);
        fprintf(stderr, "Could not create %s.\n", outfile);
        return 3;
    }

    // read infile's BITMAPFILEHEADER
    BITMAPFILEHEADER bf;
    fread(&bf, sizeof(BITMAPFILEHEADER), 1, inptr);

    // read infile's BITMAPINFOHEADER
    BITMAPINFOHEADER bi;
    fread(&bi, sizeof(BITMAPINFOHEADER), 1, inptr);

    // ensure infile is (likely) a 24-bit uncompressed BMP 4.0
    if (bf.bfType != 0x4d42 || bf.bfOffBits != 54 || bi.biSize != 40 ||
        bi.biBitCount != 24 || bi.biCompression != 0) {
        fclose(outptr);
        fclose(inptr);
        fprintf(stderr, "Unsupported file format.\n");
        return 4;
    }

    BITMAPFILEHEADER bf_resize = bf;
    BITMAPINFOHEADER bi_resize = bi;
    bi_resize.biWidth = bi.biWidth * f;
    bi_resize.biHeight = bi.biHeight * f;
    int padding = bi.biWidth % 4;       // you can simplify the calculation
    int padding_resize = bi_resize.biWidth % 4;
    bi_resize.biSizeImage = (bi_resize.biWidth * sizeof(RGBTRIPLE) + padding_resize) * bi_resize.biHeight;
    bf_resize.bfSize = bi_resize.biSizeImage + sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);

    // allocate mamory for the rgb triplets of the original (input) image
    RGBTRIPLE *pix = malloc(sizeof(RGBTRIPLE) * bi.biWidth * bi.biHeight);
    if (pix == NULL) {
        fprintf(stderr, "malloc failed.\n");
        return 5;
    }
    // temporary storage
    RGBTRIPLE triple;

    // read the entire pixels of the original image and store into the memory
    for (int i = 0; i < bi.biHeight; i++) {
        for (int j = 0; j < bi.biWidth; j++) {
            fread(&triple, sizeof(RGBTRIPLE), 1, inptr);
            pix[i * bi.biWidth + j] = triple;
        }
        // skip over padding, if any
        fseek(inptr, padding, SEEK_CUR);
    }

    // write outfile's header
    fwrite(&bf_resize, sizeof(BITMAPFILEHEADER), 1, outptr);
    fwrite(&bi_resize, sizeof(BITMAPINFOHEADER), 1, outptr);

    // write the pixels of destination (resized) image
    for (int i = 0; i < bi_resize.biHeight; i++) {
        for (int j = 0; j < bi_resize.biWidth; j++) {
            // calculate the corresponding coorinates in the original image
            int m = (i / f + 0.5);              // +0.5 for rounding
            if (m > bi.biHeight - 1) {          // limit the value
                m = bi.biHeight - 1;
            }
            int n = (j / f + 0.5);
            if (n > bi.biWidth - 1) {
                n = bi.biWidth - 1;
            }
            // pick the pixel value at the coordinate
            triple = pix[m * bi.biWidth + n];
            // write RGB triplet to outfile
            fwrite(&triple, sizeof(RGBTRIPLE), 1, outptr);
        }
        // padding for the output image, if any
        for (int j = 0; j < padding_resize; j++) {
            fputc(0x00, outptr);
        }
    }
    free(pix);
    fclose(inptr);
    fclose(outptr);

    return 0;
}

输入图片: f=0.5 时的输出图像: