根据父属性或父模式有条件地验证 json 模式

Question

我有以下 json 架构

{
  "$schema": "http://json-schema.org/draft-07/schema#",
  "type": "object",
  "title": "MySchema",
  "required": ["environment", "datacenter"],
  "properties": {
    "environment": {
      "type": "string",
      "title": "environment",
      "enum": ["DEV", "STG", "PROD"]
    },
    "datacenter": {
      "type": "object",
      "title": "datacenter",
      "properties": {
        "value": {
          "$ref": "#/definitions/datacenter"
        }
      }
    }
  },
  "definitions": {
    "datacenter": {
      "type": "string",
      "enum": [ "devDC1", "devDC2", "stgDC1", "stgDC2", "prodDC1", "prodDC2" ]
    }
  }
}

这是它的简单使用方法

{
    "$schema": "http://localhost/schemas/v3/env.json",
    "environment": "DEV",
    "datacenter": {
        "value": "devDC1"
    }
}

我想做的是

如果环境设置为DEV，那么我应该只能select devDC1, devDC2作为datacenter属性的值，如果我select STG作为环境然后stgDC1 , stgDC2 是允许的，和 PROD

一样

请注意 "$ref": "#/definitions/datacenter" 在我的架构中实际上引用了另一个文件

Answer 1

可以使用if+allOf（见第二个例子here），例如：

  "allOf": [
    {
      "if": {"properties": {"environment": {"const": "DEV"}}},
      "then": {"properties": {"datacenter": {"properties": {"value": {"pattern": "^dev"}}}}}
    },
    {
      "if": {"properties": {"environment": {"const": "STG"}}},
      "then": {"properties": {"datacenter": {"properties": {"value": {"pattern": "^stg"}}}}}
    },
    {
      "if": {"properties": {"environment": {"const": "PROD"}}},
      "then": {"properties": {"datacenter": {"properties": {"value": {"pattern": "^prod"}}}}}
    }
  ]

请注意，除此之外，您还需要将 "required": ["value"] 添加到 /properties/datacenter 中（否则无论环境如何，"datacenter": {} 也将被接受）。

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