读取 JSON 时出错无法访问 Newtonsoft.Json.Linq.JProperty 上的子值

Question

我正在尝试从其余响应对象中读取属性。响应是一个 json 对象数组，如下所示。我想读取属性 lastName, titles.investigatorTitle.name, CurrentMembership.currentMembershipType.name

{
    "data": [
        {
            "investigatorID": 3,
            "firstName": "JH",
            "middleName": "JH",
            "lastName": "HV",
            "titles": [
                {
                    "investigatorTitle": {
                        "id": 7,
                        "name": "Professor",
                        "active": true
                    },
                    "additionalDetails": null,
                    "startDate": null,
                    "endDate": null,
                    "displayIndex": 1
                }
            ],
            "CurrentMembership": [
                {
                    "investigatorCenterMembershipID": 4,
                    "investigatorCenter": {
                        "id": 1,
                        "name": "SCG"
                    },
                    "currentMembershipType": {
                        "id": 11,
                        "name": "ABC Member",
                        "code": "ABC",
                        "active": true
                    }
                }
            ]
        },
        {
             "investigatorID": 4,
            "firstName": "FG",
            "middleName": "JH",
            "lastName": "VF",
           "titles": [
                {
                    "investigatorTitle": {
                        "id": 7,
                        "name": "Professor",
                        "active": true
                    },
                    "additionalDetails": null,
                    "startDate": null,
                    "endDate": null,
                    "displayIndex": 1
                }
            ],
            "CurrentMembership": [
                {
                    "investigatorCenterMembershipID": 4,
                    "investigatorCenter": {
                        "id": 1,
                        "name": "SCG"
                    },
                    "currentMembershipType": {
                        "id": 11,
                        "name": "ABC Member",
                        "code": "ABC",
                        "active": true
                    }
                }
            ]
        }
    ],
    "meta": {
        "totalRecords": 675,
        "totalPages": 27
    },
    "links": null
}

我收到错误 System.InvalidOperationException: 'Cannot access child value on Newtonsoft.Json.Linq.JProperty.' at c.Name = i[0].lastName;

我怎样才能正确访问它？

IRestResponse response = client.Execute(request);

            var InvestigatorList = new List<searchResults>();

            dynamic jsonResponse = JsonConvert.DeserializeObject(response.Content);


            foreach (dynamic i in jsonResponse)
            {
                Contact c = new Contact();
                
                c.Name = i[0].lastName; //THE ERROR IS HAPPENING HERE

                InvestigatorList.Add(new searchResults()
                {
                    Name = c.Name,
                    Contact = c
                });
                
            }

Answer 1

好的，我不确定你在做什么，因为这是我不熟悉的方法。我对 newtonsoft 所做的是构建类以反映 Json 格式。然后反序列化到它上面。

Class:

public class DeserializeJson
{
    public DataList ExtractedData;
    public DeserializeJson(IRestResponse response)
    {
        try
        {
            ExtractedData = JsonConvert.DeserializeObject<DataList>(response.Content);
        }
        catch(Exception ex)
        {
            throw new Exception(ex.Message());
        }
    }
    
    public class DataList
    {
        public List<Data> Data {get; set;}
        public meta meta {get; set;}
        public string? links {get;set;}
    }
    public class Data
    {
        public int investigatorID {get; set;}
        public string firstName {get; set;}
        public string middleName {get; set;}
        public string lastName {get; set;}
        public List<titles> titles {get; set;}
        public List<CurrentMembership> {get; set;}
    }
    public class meta
    {
        public int totalRecords {get; set;}
        public int totalPages {get; set;}
    }
    public class CurrentMembership
    {
        public int investigatorCenterMembershipID {get; set;}
        public investigatorCenter investigatorCenter {get; set;}
        public currentMembershipType currentMembershipType {get; set;}
    }
    public class titles
    {
        public int investigatorID {get; set;}
        //not sure what additionalDetails could also hold but you have to reflect it
        public bool additionalDetails {get; set;}
        public DateTime? startDate {get; set;}
        public DateTime? endDate {get; set;}
        public int displayIndex {get; set;}
        public investigatorTitle investigatorTitle{get;set;}
    }
    public class investigatorTitle
    {
        public int id {get; set;}
        public string name {get; set;}
        public bool active {get; set;}
    }
    public class currentMembershipType
    {
        public int id {get; set;}
        public string name {get; set;}
    }
    public class investigatorCenter
    {
        public int id {get; set;}
        public string name {get; set;}
        public string code {get; set;}
        public bool active {get; set;}
    }
}

在那之后我会传递你想要的任何东西，因为那里的一切都可以通过 linq 访问。

例如：

访问：

    //deserialize
    DeserializeJson jsonResponse = new DeserializeJson(response);
    
    //access excample
    List<string> InvestigatorList = jsonResponse.ExtractedData.Data.Select(name=>name.lastName).ToList();

Answer 2

试试这个，它在 Visual Studio

中测试过

var response = client.Execute(request);

var data = JObject.Parse(response.Content)["data"];
    
List<SearchResults> investigatorList = data.Select(d => new SearchResults { 
Name = (string)d["lastName"], Contact = new Contact {Name = (string)d["lastName"]}}).ToList();

结果（序列化为json格式）

[
  {
    "Name": "HV",
    "Contact": {
      "Name": "HV"
    }
  },
  {
    "Name": "VF",
    "Contact": {
      "Name": "VF"
    }
  }
]

类

public class Contact
{
    public string Name { get; set; }
}
public class SearchResults
{
    public string Name { get; set; }
    public Contact Contact { get; set; }
}

读取 JSON 时出错无法访问 Newtonsoft.Json.Linq.JProperty 上的子值

Error Cannot access child value on Newtonsoft.Json.Linq.JProperty while reading JSON

c#

json

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