处理摘要类和序列化的unordered_map

Question

假设我有以下结构：

struct Base {
    virtual int get_x() = 0;
}

struct A : Base {
    int get_x() {
         // ...
         return 0;
    }
}

struct B : Base {
    int get_x() {
         // ...
         return 1;
    }
}

这些我也有序列化方法类:

BOOST_SERIALIZATION_SPLIT_FREE(A);
namespace boost {
    namespace serialization {
        template<class Archive>
        void save(Archive & ar, const A & a,
                        const unsigned int version) {
            // ...
        }
        template<class Archive>
        void load(Archive & ar, A & a,
                        const unsigned int version) {
            // ...
        }
    }
}

// same for B

在我的代码中，我正在制作一个 unordered_map<int, A>。我有保存和加载这张地图的功能：

inline void save_map(string filename, unordered_map<int, A>& a_dict) {
    ofstream filestream(filename);
    boost::archive::binary_oarchive archive(filestream,
                                            boost::archive::no_codecvt);

    archive << a_dict;
}

inline void load_map(string filename, unordered_map<int, A>* a_dict) {
    ifstream filestream(filename);
    boost::archive::binary_iarchive archive(filestream,
                                            boost::archive::no_codecvt);

    archive >> *a_dict;
}

我现在想以一种优雅的方式概括我的地图定义和这些函数，这样我的代码就不知道我的对象是 A 还是 B。显然我运行进入对象切片问题，例如，如果我刚开始使用 unordered_map<int, Base>，但此时我已经有点迷失在指针的杂草中并且无法弄清楚出解决方案。

Answer 1

我可能会推荐现成的指针容器。有

Boost Pointer Containers
自己动手

指针容器

这很简单：

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#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>
#include <boost/serialization/export.hpp>
#include <fstream>

#include <boost/ptr_container/ptr_unordered_map.hpp>
#include <boost/ptr_container/serialize_ptr_unordered_map.hpp>

struct Base {
    virtual ~Base() noexcept = default;
    virtual int get_x() const = 0;

    friend auto&  operator<<(std::ostream& os, Base const& b) {
        return os << typeid(b).name() << "[" << b.get_x() << "]";
    }
};

struct A : Base { int get_x() const override { return 0; } };
struct B : Base { int get_x() const override { return 1; } };

BOOST_SERIALIZATION_ASSUME_ABSTRACT(Base)
BOOST_CLASS_EXPORT(A)
BOOST_CLASS_EXPORT(B)

namespace boost { namespace serialization {
    template <class Ar> void serialize(Ar& ar, Base&, unsigned) { }
    template <class Ar> void serialize(Ar& ar, A& a, unsigned) { ar& base_object<Base>(a); }
    template <class Ar> void serialize(Ar& ar, B& b, unsigned) { ar& base_object<Base>(b); }
}} // namespace boost::serialization

template <typename Map>
inline void save_map(std::string const& filename, Map const& map) {
    std::ofstream ofs(filename, std::ios::binary);
    boost::archive::binary_oarchive archive(ofs, boost::archive::no_codecvt);
    archive << map;
}

template <typename Map>
inline void load_map(std::string const& filename, Map& map) {
    std::ifstream ifs(filename, std::ios::binary);
    boost::archive::binary_iarchive archive(ifs, boost::archive::no_codecvt);
    archive >> map;
}

#include <iostream>

int main()
{
    using Dict = boost::ptr_unordered_map<int, Base>;

    {
        Dict dict;
        dict.insert(100, std::make_unique<A>());
        dict.insert(200, std::make_unique<B>());
        dict.insert(300, std::make_unique<B>());
        dict.insert(400, std::make_unique<A>());

        save_map("test.bin", dict);
    }

    {
        Dict roundtrip;
        load_map("test.bin", roundtrip);

        for (auto const& [k,v]: roundtrip) {
            std::cout << k << ": " << *v << "\n";
        }
    }
}

打印例如

100: 1A[0]
200: 1B[1]
300: 1B[1]
400: 1A[0]

并且没有内存泄漏。

自己动手

这有一些好处（更现代的界面有时在其他方面更“指针”界面）：

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#include <boost/archive/binary_iarchive.hpp>
#include <boost/archive/binary_oarchive.hpp>
#include <boost/serialization/boost_unordered_map.hpp>
#include <boost/serialization/unique_ptr.hpp>
#include <boost/serialization/export.hpp>
#include <fstream>

struct Base {
    virtual ~Base() noexcept = default;
    virtual int get_x() const = 0;

    friend auto&  operator<<(std::ostream& os, Base const& b) {
        return os << typeid(b).name() << "[" << b.get_x() << "]";
    }
};

struct A : Base { int get_x() const override { return 0; } };
struct B : Base { int get_x() const override { return 1; } };

BOOST_SERIALIZATION_ASSUME_ABSTRACT(Base)
BOOST_CLASS_EXPORT(A)
BOOST_CLASS_EXPORT(B)

namespace boost { namespace serialization {
    template <class Ar> void serialize(Ar& ar, Base&, unsigned) { }
    template <class Ar> void serialize(Ar& ar, A& a, unsigned) { ar& base_object<Base>(a); }
    template <class Ar> void serialize(Ar& ar, B& b, unsigned) { ar& base_object<Base>(b); }
}} // namespace boost::serialization

template <typename Map>
inline void save_map(std::string const& filename, Map const& map) {
    std::ofstream ofs(filename, std::ios::binary);
    boost::archive::binary_oarchive archive(ofs, boost::archive::no_codecvt);
    archive << map;
}

template <typename Map>
inline void load_map(std::string const& filename, Map& map) {
    std::ifstream ifs(filename, std::ios::binary);
    boost::archive::binary_iarchive archive(ifs, boost::archive::no_codecvt);
    archive >> map;
}

#include <iostream>

int main()
{
    using Dict = boost::unordered_map<int, std::unique_ptr<Base> >;

    {
        Dict dict;
        dict.emplace(100, std::make_unique<A>());
        dict.emplace(200, std::make_unique<B>());
        dict.emplace(300, std::make_unique<B>());
        dict.emplace(400, std::make_unique<A>());

        save_map("test.bin", dict);
    }

    {
        Dict roundtrip;
        load_map("test.bin", roundtrip);

        for (auto const& [k,v]: roundtrip) {
            std::cout << k << ": " << *v << "\n";
        }
    }
}

打印，同样没有内存泄漏，类似于：

100: 1A[0]
200: 1B[1]
300: 1B[1]
400: 1A[0]

处理摘要类和序列化的unordered_map

Dealing with unordered_map of abstract classes and serialization

c++

oop

serialization

boost

abstract

指针容器

自己动手