将多个字符串传递给函数并附加到列表

Question

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, trick ):
     self.tricks.extend(trick)

我一直收到这样的错误：add_tricks 只接受 1 个位置参数，但给出了 3 个。我尝试将 **kwargs 传递给该函数，但这也不起作用。如何将多个字符串传递给函数？

Answer 1

For (*args) parameters as ("Hello","Byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, *trick):
     self.tricks.extend(trick)

For (**kwargs) parameters as (a="Hello",b="Byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, **trick):
     self.tricks.extend(trick)

Or if you want to give string in both types like (a="Hello","byy")

class Dog:
   tricks = []
   def __init__(self,name):
     self.name=name
   def add_tricks(self, *trick1,**trick2):
     self.tricks.extend(trick)
     self.tricks.extend(trick2)

将多个字符串传递给函数并附加到列表

Passing multiple strings to a function and appending to list

python

class

oop

keyword-argument