Python：以元组的形式填充列表中的数据

Question

I need to create a function that reads the data given and creates a list that contains tuples each of which has as its first element the name of the airport and as its second and third its geographical coordinates as float numbers.

airport_data = """
Alexandroupoli 40.855869°N 25.956264°E
Athens 37.936389°N 23.947222°E
Chania 35.531667°N 24.149722°E
Chios 38.343056°N 26.140556°E
Corfu 39.601944°N 19.911667°E
Heraklion 35.339722°N 25.180278°E"""

airports = []

import re
airport_data1 = re.sub("[°N@°E]","",airport_data)
        
def process_airports(string):
    airports_temp = list(string.split())
    airports = [tuple(airports_temp[x:x+3]) for x in range(0, len(airports_temp), 3)]
    return airports

print(process_airports(airport_data1))

This is my code so far but I'm new to Python, so I'm struggling to debug my code.

Answer 1

如果你想让元组的第二个和第三个元素是一个浮点数，你必须使用float()函数将它们转换。一种方法是在您的列表理解中创建一个带有圆括号的元组，并在那里转换值：

    def process_airports(string):
        airports_temp = string.split()
        airports = [(airports_temp[x], float(airports_temp[x+1]), float(airports_temp[x+2])) for x in range(0, len(airports_temp), 3)]
        return airports

这会产生一个非常笨拙的表达式，因此也许可以使用经典的 for 循环更易读地解决这个问题。

另请注意 slpit() 已经 returns 一个列表。进一步说明：如果您只是切断坐标中的字母，当您的机场位于不同的象限时，这可能会反咬您一口。

Answer 2

您需要考虑 N/S、W/E 的经度和纬度。可能是

def process_airports(string):
    airports = []
    for line in string.split('\n'):
        if not line: continue
        name, lon, lat = line.split()
        airports.append((name,
                         float(lon[:-2]) * (1 if lon[-1] == "N" else -1),
                         float(lat[:-2]) * (-1 if lat[-1] == "E" else 1)
                       ))
    return airports
        
>>> process_airports(airport_data1)
[('Alexandroupoli', 40.855869, -25.956264), ('Athens', 37.936389, -23.947222), ('Chania', 35.531667, -24.149722), ('Chios', 38.343056, -26.140556), ('Corfu', 39.601944, -19.911667), ('Heraklion', 35.339722, -25.180278)]

我更喜欢双重分裂来证明差异 lines/tuple 元素

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