Python：无法将弧度与 pi 值进行比较

Question

我正在编写一个算法，它应该能够根据用户输入的两个值确定弧度在哪个象限。我认为代码正在计算弧度，但我知道这些值没有与我给出的 pi 值进行比较，因为我没有得到任何输出。

代码如下：

print('Enter the radians of the angle (a*π/b): ')
a = int(input('a value(top): '))
b = int(input('b value(bottom): '))

radians = ((a*math.pi)/b)

print('')
print('Finding...')

if radians > 0 and radians < (math.pi/2):
    print(f'The angle {radians}rad is in the I quadrant')

if radians > (math.pi/2) and degrees < math.pi:
    print(f'The angle  {radians}rad is in the II quadrant')

if radians > math.pi and radians < (3*math.pi/2):
    print(f'The angle {radians}rad is in the III quadrant')

if radians > (3*math.pi/2) and radians < (2*math.pi):
    print(f'The angle {radians}rad is in the IV quadrant')

Answer 1

首先，您应该将度数重命名为弧度。另一个问题是您假设所有输入都在 0 到 2pi 之间。您应该考虑其他输入。

import math

print('Enter the radians of the angle (a*π/b): ')
a = int(input('a value(top): '))
b = int(input('b value(bottom): '))

radians = ((a*math.pi)/b)

print('')
print('Finding...')

while radians > 2 * math.pi:
    radians -= 2 * math.pi
while radians < 0:
    radians += 2 * math.pi

if 0 < radians < (math.pi / 2):
    print(f'The angle {radians}rad is in the I quadrant')

if (math.pi / 2) < radians < math.pi:
    print(f'The angle  {radians}rad is in the II quadrant')

if math.pi < radians < (3 * math.pi / 2):
    print(f'The angle {radians}rad is in the III quadrant')

if (3 * math.pi / 2) < radians < (2 * math.pi):
    print(f'The angle {radians}rad is in the IV quadrant')

Answer 2

首先，您可能没有在代码中写 import math 就像您忘记了这里一样。

其次，如果您输入轴上的值，您将不会得到任何输出，因为没有条件。例如，输入 3π/2 不会给出任何输出，因为它在一个轴上。 P.S。在第一个 if 语句之后使用 elif 会更好。

这是我的代码版本。添加了 import math 和条件来检查角度是否位于轴上。这涵盖了所有可能的输入（字符串除外）所以不用担心 'No Output'.

编辑：忘记提及 degrees 到 radians 的变量替换，因为在第二个 if 条件中没有名为 degrees 的变量。

import math
print('Enter the radians of the angle (a*π/b): ')
a = int(input('a value(top): '))
b = int(input('b value(bottom): '))

radians = ((a*math.pi)/b)

print('')
print('Finding...')

if radians > 0 and radians < (math.pi/2):
    print(f'The angle {radians}rad is in the I quadrant')

elif radians > (math.pi/2) and radians < math.pi:
    print(f'The angle  {radians}rad is in the II quadrant')

elif radians > math.pi and radians < (3*math.pi/2):
    print(f'The angle {radians}rad is in the III quadrant')

elif radians > (3*math.pi/2) and radians < (2*math.pi):
    print(f'The angle {radians}rad is in the IV quadrant')

elif (radians == (3*math.pi/2)) or (radians == (math.pi/2)):
    print(f'The angle {radians}rad is on Y axis.')

elif (radians == (math.pi)) or (radians == 0):
    print(f'The angle {radians}rad is on X axis.')

希望对您有所帮助，如果有帮助，请采纳此回答。

Answer 3

更正第二个 if 语句的拼写错误后，我在控制台上也没有得到任何输出，直到我进行了以下更改。

if radians > 0 and radians < (math.pi/2):
    print(f'The angle {radians}rad is in the I quadrant')
elif radians > (math.pi/2) and radians < math.pi:
    print(f'The angle  {radians}rad is in the II quadrant')
elif radians > math.pi and radians < (3*math.pi/2):
    print(f'The angle {radians}rad is in the III quadrant')
elif radians > (3*math.pi/2) and radians < (2*math.pi):
    print(f'The angle {radians}rad is in the IV quadrant')
else:
    print(f"The angle {radians}rad is on one of the axis.")

Python：无法将弧度与 pi 值进行比较

Python: Not being able to compare radians with pi values

python

algorithm

math

calculus

radians