如何让 rust 代码使用本地使用命令

Question

我写了一个像这样的 rust 代码：

fn find_channel(request: &ChannelRequest) -> Box<dyn BoxableExpression<crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::table, DB, SqlType=Bool> + '_> {
    use crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl::*;
    match request {
        ChannelRequest { editorPick, .. } if editorPick.unwrap_or(0) == 1 => Box::new(crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl::editor_pick.eq(editorPick)),
        ChannelRequest{ minimalReputation, ..} if minimalReputation.unwrap_or(0) > 0 => Box::new(crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl::reputation.gt(minimalReputation)),
        _ => Box::new(crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl::editor_pick.eq(0))
    }
}

现在我想让代码更短，并删除 crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl:: 并想让 editor_pick 使用本地函数导入命令。令我惊讶的是，IDE 仍然告诉我要导入 crate::model::diesel::dolphin::dolphin_schema::rss_sub_source::dsl::，为什么即使在函数中导入了还需要导入？我应该如何从代码中删除包路径并使代码更短更清晰？是否可以从代码中删除包路径？这是来自 IDE:

的智能提示

Answer 1

cargo/rustc是否接受代码？在这种情况下，IntelliJ Rust 可能存在问题。

如何让 rust 代码使用本地使用命令

how to let the rust code using local use command

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