获取 python 枚举 class 的名称

Question

假设我有一个这样的class

class ErrorCreatingObjectResult(enum.Enum):
    NONE = 0
    OBJECT_ALREADY_EXIST = 1
    UID_NOT_REGESTIRE = 2
    CREATOR_NOT_REGESTIRE = 3

以及具有此 class

属性的对象

class CreatingObjectMessage:
    def __init__(self) -> None:
        self.message = 'done creating object'
        self.error = False
        self.errorType = ErrorCreatingObjectResult.NONE

我想通过调用

从这个class生成dict对象

def convert2serialize(obj):
    if isinstance(obj, dict):
        return {k: convert2serialize(v) for k, v in obj.items()}
    elif hasattr(obj, "_ast"):
        return convert2serialize(obj._ast())
    elif not isinstance(obj, str) and hasattr(obj, "__iter__"):
        return [convert2serialize(v) for v in obj]
    elif hasattr(obj, "__dict__"):
        return {
            k: convert2serialize(v)
            for k, v in obj.__dict__.items()
            if not callable(v) and not k.startswith('_')
        }
    else:
        return obj

r = CreatingObjectMessage()
convert2serialize(r)

这给我一个空的结果

Answer 1

编辑 convert2serialize 函数修复了它

def convert2serialize(obj):
    if isinstance(obj, enum.Enum):
        return {type(obj).mro()[0].__name__: obj.name}
    if isinstance(obj, dict):
        return {k: convert2serialize(v) for k, v in obj.items()}
    elif hasattr(obj, "_ast"):
        return convert2serialize(obj._ast())
    elif not isinstance(obj, str) and hasattr(obj, "__iter__"):
        return [convert2serialize(v) for v in obj]
    elif hasattr(obj, "__dict__"):
        return {
            k: convert2serialize(v)
            for k, v in obj.__dict__.items()
            if not callable(v) and not k.startswith('_')
        }
    else:
        return obj

这是我可以获得 class

名称的部分

type(obj).mro()[0].__name__

Answer 2

获取枚举成员的 class 的名称非常简单：

member.__class__.__name__

获取 python 枚举 class 的名称

Getting the name of python enum class

python

enums