Python,Kivy:从不同 classes/screens 调用函数时出现问题

Python, Kivy: Problem with calling functions from different classes/screens

我在正确调用来自不同 类 的函数时遇到问题。

我正在制作一个简单的游戏,它使用通关所需的时间来计算分数。背景中有一个秒表 运行,我想在弹出菜单中添加一个暂停按钮,并在此弹出菜单中添加一个恢复按钮。

问题是,当从弹出菜单中调用暂停函数时,它也会在弹出菜单中返回,而不是在主窗口小部件中返回。

这里是代码的简化版本:

import kivy
from kivy.app import App
from kivy.lang import Builder
from kivy.properties import NumericProperty
from kivy.uix.widget import Widget
from kivy.uix.popup import Popup
from kivy.clock import Clock

root_widget = Builder.load_file('app.kv')


class ExampleWidget(Widget):
    time = NumericProperty(0)
    paused = False
    stop = False

    # Keeping time
    def increment_time(self, interval):

        self.time += .1
        print(self.time)  # To check if stopwatch is running or not

    # Stop should mean that the stopwatch must reset when it starts again.
    # When paused it should resume when it starts again
    def stop_start_or_pause(self):

        # stop stopwatch
        if self.stop:
            Clock.unschedule(self.increment_time)
            print('Stopped')

        # Make sure time is 0 when restarting
        elif not self.stop and not self.paused:
            # Keeping time
            self.time = 0
            Clock.schedule_interval(self.increment_time, .1)

        # Pause stopwatch
        elif self.paused:
            Clock.unschedule(self.increment_time)
            print("!!", self.time)  # To make it easier to see if stopwatch actually resumes where it left off
            print('unscheduled')  # Just to confirm and to make it a bit easier to see

        # resume stopwatch
        elif not self.paused:
            Clock.schedule_interval(self.increment_time, .1)


class PopupMenu(Popup):
    example = ExampleWidget()


class MyApp(App):
    ExampleWidget = ExampleWidget()

    def build(self):
        return ExampleWidget()


MyApp().run()

.kv 文件:

#:import Factory kivy.factory.Factory
<PopupMenu@Popup>
    auto_dismiss: False
    size_hint_y: .8
    size_hint_x: .9
    title: 'Pause'
    example: app.ExampleWidget

    BoxLayout:
        Button:
            text: 'resume'
            on_press: root.example.paused = False
            on_release: root.dismiss(); root.example.stop_start_or_pause()
            size: self.size

<ExampleWidget>:
    GridLayout:
        col: 2
        rows: 3
        size: root.size
        Button:
            text: 'start'
            size: self.size
            on_press: root.stop = False; root.stop_start_or_pause()
        Button:
            text: 'stop'
            size: self.size
            on_press: root.stop = True; root.stop_start_or_pause()
        Button:
            text: 'Pause menu'
            size: self.size
            on_press: root.paused = True
            on_release: Factory.PopupMenu().open(); root.stop_start_or_pause()
        Label:
            text: str(round(root.time))
            size: self.size

我尝试制作一个函数并使用 Clock.schedule.interval() 继续检查是否暂停 == True,但它不断返回:

AttributeError: 'float' object has no attribute 'stopped'

无论如何,这似乎都不是有效的解决方案,因此我不想在此功能上花费太多时间。我还尝试查找 'stupid' 错误(即“,”而不是“.”),但那是在我意识到恢复按钮返回 'second' 秒表而不是更新我真正想使用的秒表之前.

我希望有人能提供帮助,并且我的问题很清楚。英语不是我的第一语言,所以我有时很难找到 explain/ask 问题的最佳方式。

提前致谢!

如果我理解你的问题,问题出在你的 MyApp class:

class MyApp(App):
    ExampleWidget = ExampleWidget()

    def build(self):
        return ExampleWidget()

此代码正在创建 ExampleWidget 的两个实例。一个在build()方法中返回,一个保存为MyAppExampleWidget属性。现在,当您使用 MyAppExampleWidget 属性时,您没有引用作为 GUI 根的 ExampleWidget,因此它对屏幕上显示的内容没有影响。解决方法是只创建一个 ExampleWidget 实例,如下所示:

class MyApp(App):
    ExampleWidget = ExampleWidget()

    def build(self):
        return self.ExampleWidget