Canvas矩阵动画JS
Canvas Matrix Animation JS
我在 codePen 上找到了这个例子,
并且当字母在一行中移动时的第一次迭代看起来很糟糕,
是否可以从一开始就从不同的位置开始移动列? (不是来自第二次迭代)
我的解决方案也很糟糕:
我添加了不透明度为 0 到 100 的 @keyframes
并添加了持续时间为 3s 和动画计时功能的动画:step-end;
// geting canvas by Boujjou Achraf
var c = document.getElementById("c");
var ctx = c.getContext("2d");
//making the canvas full screen
c.height = window.innerHeight;
c.width = window.innerWidth;
//chinese characters - taken from the unicode charset
var matrix = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789@#$%^&*()*&^%+-/~{[|`]}";
//converting the string into an array of single characters
matrix = matrix.split("");
var font_size = 10;
var columns = c.width/font_size; //number of columns for the rain
//an array of drops - one per column
var drops = [];
//x below is the x coordinate
//1 = y co-ordinate of the drop(same for every drop initially)
for(var x = 0; x < columns; x++)
drops[x] = 1;
//drawing the characters
function draw()
{
//Black BG for the canvas
//translucent BG to show trail
ctx.fillStyle = "rgba(0, 0, 0, 0.04)";
ctx.fillRect(0, 0, c.width, c.height);
ctx.fillStyle = "#f4427d";//green text
ctx.font = font_size + "px arial";
//looping over drops
for(var i = 0; i < drops.length; i++)
{
//a random chinese character to print
var text = matrix[Math.floor(Math.random()*matrix.length)];
//x = i*font_size, y = value of drops[i]*font_size
ctx.fillText(text, i*font_size, drops[i]*font_size);
//sending the drop back to the top randomly after it has crossed the screen
//adding a randomness to the reset to make the drops scattered on the Y axis
if(drops[i]*font_size > c.height && Math.random() > 0.975)
drops[i] = 0;
//incrementing Y coordinate
drops[i]++;
}
}
setInterval(draw, 35);
/* By Boujjou Achraf*/
/*basic reset */
*{
margin: 0;
padding: 0;
}
body {background: black;}
canvas {display:block;}
/* By Boujjou Achraf*/
<html>
<head>
</head>
<body>
<canvas id="c"></canvas>
</body>
</html>
每个动画字母的垂直屏幕位置存储在一个名为 drops
的数组中。
在启动时,每个字母通过以下两行获得相同的初始位置:
for (var x = 0; x < columns; x++)
drops[x] = 1;
您可以将每个字母的位置设为从 0 到 canvas 元素高度的随机数,方法是将上面的内容更改为:
for (var x = 0; x < columns; x++)
drops[x] = parseInt(Math.random() * c.height);
Math.random()
returns 介于 0 和 1 之间的浮点数和 c.height
returns <canvas>
元素的高度。通过将这两个值相乘,我们得到一个介于 0 和 canvas' 高度之间的随机数。
这是您修改后的示例:
var c = document.getElementById("c");
var ctx = c.getContext("2d");
//making the canvas full screen
c.height = window.innerHeight;
c.width = window.innerWidth;
//chinese characters - taken from the unicode charset
var matrix = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789@#$%^&*()*&^%+-/~{[|`]}";
//converting the string into an array of single characters
matrix = matrix.split("");
var font_size = 10;
var columns = c.width / font_size; //number of columns for the rain
//an array of drops - one per column
var drops = [];
//x below is the x coordinate
//1 = y co-ordinate of the drop(same for every drop initially)
for (var x = 0; x < columns; x++)
drops[x] = parseInt(Math.random() * c.height);
//drawing the characters
function draw() {
//Black BG for the canvas
//translucent BG to show trail
ctx.fillStyle = "rgba(0, 0, 0, 0.04)";
ctx.fillRect(0, 0, c.width, c.height);
ctx.fillStyle = "#f4427d"; //green text
ctx.font = font_size + "px arial";
//looping over drops
for (var i = 0; i < drops.length; i++) {
//a random chinese character to print
var text = matrix[Math.floor(Math.random() * matrix.length)];
//x = i*font_size, y = value of drops[i]*font_size
ctx.fillText(text, i * font_size, drops[i] * font_size);
//sending the drop back to the top randomly after it has crossed the screen
//adding a randomness to the reset to make the drops scattered on the Y axis
if (drops[i] * font_size > c.height && Math.random() > 0.975)
drops[i] = 0;
//incrementing Y coordinate
drops[i]++;
}
}
setInterval(draw, 35);
* {
margin: 0;
padding: 0;
}
body {
background: black;
}
canvas {
display: block;
}
<canvas id="c"></canvas>
我在 codePen 上找到了这个例子,
并且当字母在一行中移动时的第一次迭代看起来很糟糕,
是否可以从一开始就从不同的位置开始移动列? (不是来自第二次迭代)
我的解决方案也很糟糕:
我添加了不透明度为 0 到 100 的 @keyframes
并添加了持续时间为 3s 和动画计时功能的动画:step-end;
// geting canvas by Boujjou Achraf
var c = document.getElementById("c");
var ctx = c.getContext("2d");
//making the canvas full screen
c.height = window.innerHeight;
c.width = window.innerWidth;
//chinese characters - taken from the unicode charset
var matrix = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789@#$%^&*()*&^%+-/~{[|`]}";
//converting the string into an array of single characters
matrix = matrix.split("");
var font_size = 10;
var columns = c.width/font_size; //number of columns for the rain
//an array of drops - one per column
var drops = [];
//x below is the x coordinate
//1 = y co-ordinate of the drop(same for every drop initially)
for(var x = 0; x < columns; x++)
drops[x] = 1;
//drawing the characters
function draw()
{
//Black BG for the canvas
//translucent BG to show trail
ctx.fillStyle = "rgba(0, 0, 0, 0.04)";
ctx.fillRect(0, 0, c.width, c.height);
ctx.fillStyle = "#f4427d";//green text
ctx.font = font_size + "px arial";
//looping over drops
for(var i = 0; i < drops.length; i++)
{
//a random chinese character to print
var text = matrix[Math.floor(Math.random()*matrix.length)];
//x = i*font_size, y = value of drops[i]*font_size
ctx.fillText(text, i*font_size, drops[i]*font_size);
//sending the drop back to the top randomly after it has crossed the screen
//adding a randomness to the reset to make the drops scattered on the Y axis
if(drops[i]*font_size > c.height && Math.random() > 0.975)
drops[i] = 0;
//incrementing Y coordinate
drops[i]++;
}
}
setInterval(draw, 35);
/* By Boujjou Achraf*/
/*basic reset */
*{
margin: 0;
padding: 0;
}
body {background: black;}
canvas {display:block;}
/* By Boujjou Achraf*/
<html>
<head>
</head>
<body>
<canvas id="c"></canvas>
</body>
</html>
每个动画字母的垂直屏幕位置存储在一个名为 drops
的数组中。
在启动时,每个字母通过以下两行获得相同的初始位置:
for (var x = 0; x < columns; x++)
drops[x] = 1;
您可以将每个字母的位置设为从 0 到 canvas 元素高度的随机数,方法是将上面的内容更改为:
for (var x = 0; x < columns; x++)
drops[x] = parseInt(Math.random() * c.height);
Math.random()
returns 介于 0 和 1 之间的浮点数和 c.height
returns <canvas>
元素的高度。通过将这两个值相乘,我们得到一个介于 0 和 canvas' 高度之间的随机数。
这是您修改后的示例:
var c = document.getElementById("c");
var ctx = c.getContext("2d");
//making the canvas full screen
c.height = window.innerHeight;
c.width = window.innerWidth;
//chinese characters - taken from the unicode charset
var matrix = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789@#$%^&*()*&^%+-/~{[|`]}";
//converting the string into an array of single characters
matrix = matrix.split("");
var font_size = 10;
var columns = c.width / font_size; //number of columns for the rain
//an array of drops - one per column
var drops = [];
//x below is the x coordinate
//1 = y co-ordinate of the drop(same for every drop initially)
for (var x = 0; x < columns; x++)
drops[x] = parseInt(Math.random() * c.height);
//drawing the characters
function draw() {
//Black BG for the canvas
//translucent BG to show trail
ctx.fillStyle = "rgba(0, 0, 0, 0.04)";
ctx.fillRect(0, 0, c.width, c.height);
ctx.fillStyle = "#f4427d"; //green text
ctx.font = font_size + "px arial";
//looping over drops
for (var i = 0; i < drops.length; i++) {
//a random chinese character to print
var text = matrix[Math.floor(Math.random() * matrix.length)];
//x = i*font_size, y = value of drops[i]*font_size
ctx.fillText(text, i * font_size, drops[i] * font_size);
//sending the drop back to the top randomly after it has crossed the screen
//adding a randomness to the reset to make the drops scattered on the Y axis
if (drops[i] * font_size > c.height && Math.random() > 0.975)
drops[i] = 0;
//incrementing Y coordinate
drops[i]++;
}
}
setInterval(draw, 35);
* {
margin: 0;
padding: 0;
}
body {
background: black;
}
canvas {
display: block;
}
<canvas id="c"></canvas>