rbind/bind_rows 两个不相等 data.frames
rbind/bind_rows two unequal data.frames
下面,我想知道如何rbind
dat2
到dat1
这样我才能达到我下面的Desired_output
?
请注意,无需添加新列。 (查看所需的输出)
fit <- lm(mpg ~ hp, data = mtcars)
dat1 <- as.data.frame(coef(summary(fit)))
dat2 <- data.frame(Estimate = 2, pr = 0.1234567901, row.names = "Q")
Desired_output =
"
Estimate Std. Error t value Pr(>|t|)
(Intercept) 30.09886054 1.6339210 18.421246 6.642736e-18
hp -0.06822828 0.0101193 -6.742389 1.787835e-07
Q 2.00000000 NA NA 0.1234567901
"
可能的解决方案,需要 names(dat2)[2] <- names(dat1)[4]
在绑定行之前(列名不匹配):
library(tidyverse)
fit <- lm(mpg ~ hp, data = mtcars)
dat1 <- as.data.frame(coef(summary(fit)))
dat2 <- data.frame(Estimate = 2, pr = 0.1234567901, row.names = "Q")
names(dat2)[2] <- names(dat1)[4] # <--- This is CRUCIAL
dat1 %>%
bind_rows(dat2)
#> Estimate Std. Error t value Pr(>|t|)
#> (Intercept) 30.09886054 1.6339210 18.421246 6.642736e-18
#> hp -0.06822828 0.0101193 -6.742389 1.787835e-07
#> Q 2.00000000 NA NA 1.234568e-01
在基数 R 中:
rbind(dat1, Q = list(dat2[1], NA, NA, dat2[2]))
Estimate Std. Error t value Pr(>|t|)
(Intercept) 30.09886 1.6339210 18.421246 6.642736e-18
hp -0.06822828 0.0101193 -6.742389 1.787835e-07
Q 2 NA NA 0.1234568
下面,我想知道如何rbind
dat2
到dat1
这样我才能达到我下面的Desired_output
?
请注意,无需添加新列。 (查看所需的输出)
fit <- lm(mpg ~ hp, data = mtcars)
dat1 <- as.data.frame(coef(summary(fit)))
dat2 <- data.frame(Estimate = 2, pr = 0.1234567901, row.names = "Q")
Desired_output =
"
Estimate Std. Error t value Pr(>|t|)
(Intercept) 30.09886054 1.6339210 18.421246 6.642736e-18
hp -0.06822828 0.0101193 -6.742389 1.787835e-07
Q 2.00000000 NA NA 0.1234567901
"
可能的解决方案,需要 names(dat2)[2] <- names(dat1)[4]
在绑定行之前(列名不匹配):
library(tidyverse)
fit <- lm(mpg ~ hp, data = mtcars)
dat1 <- as.data.frame(coef(summary(fit)))
dat2 <- data.frame(Estimate = 2, pr = 0.1234567901, row.names = "Q")
names(dat2)[2] <- names(dat1)[4] # <--- This is CRUCIAL
dat1 %>%
bind_rows(dat2)
#> Estimate Std. Error t value Pr(>|t|)
#> (Intercept) 30.09886054 1.6339210 18.421246 6.642736e-18
#> hp -0.06822828 0.0101193 -6.742389 1.787835e-07
#> Q 2.00000000 NA NA 1.234568e-01
在基数 R 中:
rbind(dat1, Q = list(dat2[1], NA, NA, dat2[2]))
Estimate Std. Error t value Pr(>|t|)
(Intercept) 30.09886 1.6339210 18.421246 6.642736e-18
hp -0.06822828 0.0101193 -6.742389 1.787835e-07
Q 2 NA NA 0.1234568