如何在 Protocol Buffer C++ 教程中编写消息?
How do I write a message in the Protocol Buffer C++ tutorial?
我是 Protocol Buffers 的新手,对 C++ 没有经验,我想在 https://developers.google.com/protocol-buffers/docs/cpptutorial
完成教程
我已经创建了教程中提到的原型文件,并从该原型中获得了 addressbook.pb.h
和 addressbook.pb.cc
。我正在尝试关注 "Writing A Message" 段,因此我从教程中复制并粘贴了以下代码。我立即 运行 进入主要功能中的问题,我将在下面解释:
#include <iostream>
#include <fstream>
#include <string>
#include "addressbook.pb.h"
using namespace std;
// This function fills in a Person message based on user input.
void PromptForAddress(tutorial::Person* person) {
cout << "Enter person ID number: ";
int id;
cin >> id;
person->set_id(id);
cin.ignore(256, '\n');
cout << "Enter name: ";
getline(cin, *person->mutable_name());
cout << "Enter email address (blank for none): ";
string email;
getline(cin, email);
if (!email.empty()) {
person->set_email(email);
}
while (true) {
cout << "Enter a phone number (or leave blank to finish): ";
string number;
getline(cin, number);
if (number.empty()) {
break;
}
tutorial::Person::PhoneNumber* phone_number = person->add_phone();
phone_number->set_number(number);
cout << "Is this a mobile, home, or work phone? ";
string type;
getline(cin, type);
if (type == "mobile") {
phone_number->set_type(tutorial::Person::MOBILE);
} else if (type == "home") {
phone_number->set_type(tutorial::Person::HOME);
} else if (type == "work") {
phone_number->set_type(tutorial::Person::WORK);
} else {
cout << "Unknown phone type. Using default." << endl;
}
}
}
// Main function: Reads the entire address book from a file,
// adds one person based on user input, then writes it back out to the same
// file.
int main(int argc, char* argv[]) {
// Verify that the version of the library that we linked against is
// compatible with the version of the headers we compiled against.
GOOGLE_PROTOBUF_VERIFY_VERSION;
if (argc != 2) {
cerr << "Usage: " << argv[0] << " ADDRESS_BOOK_FILE" << endl;
return -1;
}
tutorial::AddressBook address_book;
{
// Read the existing address book.
fstream input(argv[1], ios::in | ios::binary);
if (!input) {
cout << argv[1] << ": File not found. Creating a new file." << endl;
} else if (!address_book.ParseFromIstream(&input)) {
cerr << "Failed to parse address book." << endl;
return -1;
}
}
// Add an address.
PromptForAddress(address_book.add_person());
{
// Write the new address book back to disk.
fstream output(argv[1], ios::out | ios::trunc | ios::binary);
if (!address_book.SerializeToOstream(&output)) {
cerr << "Failed to write address book." << endl;
return -1;
}
}
// Optional: Delete all global objects allocated by libprotobuf.
google::protobuf::ShutdownProtobufLibrary();
return 0;
}
在 main 函数中,由于这部分代码退出而不提示任何输入:
if (argc != 2) {
cerr << "Usage: " << argv[0] << " ADDRESS_BOOK_FILE" << endl;
return -1;
}
在请求任何输入之前显示为函数中的前几行之一。我读到 argc
将是输入的数量。我很困惑,因为我完全复制并粘贴了教程中写的内容,但它似乎 运行ning 不正确。
该代码需要在命令行上传递文件名,而不是从标准输入中读取。您没有指定您使用的平台,但您可以在 Windows 上执行 my_program.exe C:\some\file\somewhere
或在 Linux/Mac/Other Unix 上执行 ./my_program /some/file/somewhere
,例如 OS。如果您 运行 来自 IDE 的 run/debug 函数的程序,那么您需要将其配置为将文件名作为命令行参数传递。如何做到这一点将取决于您使用的 IDE。
我是 Protocol Buffers 的新手,对 C++ 没有经验,我想在 https://developers.google.com/protocol-buffers/docs/cpptutorial
完成教程我已经创建了教程中提到的原型文件,并从该原型中获得了 addressbook.pb.h
和 addressbook.pb.cc
。我正在尝试关注 "Writing A Message" 段,因此我从教程中复制并粘贴了以下代码。我立即 运行 进入主要功能中的问题,我将在下面解释:
#include <iostream>
#include <fstream>
#include <string>
#include "addressbook.pb.h"
using namespace std;
// This function fills in a Person message based on user input.
void PromptForAddress(tutorial::Person* person) {
cout << "Enter person ID number: ";
int id;
cin >> id;
person->set_id(id);
cin.ignore(256, '\n');
cout << "Enter name: ";
getline(cin, *person->mutable_name());
cout << "Enter email address (blank for none): ";
string email;
getline(cin, email);
if (!email.empty()) {
person->set_email(email);
}
while (true) {
cout << "Enter a phone number (or leave blank to finish): ";
string number;
getline(cin, number);
if (number.empty()) {
break;
}
tutorial::Person::PhoneNumber* phone_number = person->add_phone();
phone_number->set_number(number);
cout << "Is this a mobile, home, or work phone? ";
string type;
getline(cin, type);
if (type == "mobile") {
phone_number->set_type(tutorial::Person::MOBILE);
} else if (type == "home") {
phone_number->set_type(tutorial::Person::HOME);
} else if (type == "work") {
phone_number->set_type(tutorial::Person::WORK);
} else {
cout << "Unknown phone type. Using default." << endl;
}
}
}
// Main function: Reads the entire address book from a file,
// adds one person based on user input, then writes it back out to the same
// file.
int main(int argc, char* argv[]) {
// Verify that the version of the library that we linked against is
// compatible with the version of the headers we compiled against.
GOOGLE_PROTOBUF_VERIFY_VERSION;
if (argc != 2) {
cerr << "Usage: " << argv[0] << " ADDRESS_BOOK_FILE" << endl;
return -1;
}
tutorial::AddressBook address_book;
{
// Read the existing address book.
fstream input(argv[1], ios::in | ios::binary);
if (!input) {
cout << argv[1] << ": File not found. Creating a new file." << endl;
} else if (!address_book.ParseFromIstream(&input)) {
cerr << "Failed to parse address book." << endl;
return -1;
}
}
// Add an address.
PromptForAddress(address_book.add_person());
{
// Write the new address book back to disk.
fstream output(argv[1], ios::out | ios::trunc | ios::binary);
if (!address_book.SerializeToOstream(&output)) {
cerr << "Failed to write address book." << endl;
return -1;
}
}
// Optional: Delete all global objects allocated by libprotobuf.
google::protobuf::ShutdownProtobufLibrary();
return 0;
}
在 main 函数中,由于这部分代码退出而不提示任何输入:
if (argc != 2) {
cerr << "Usage: " << argv[0] << " ADDRESS_BOOK_FILE" << endl;
return -1;
}
在请求任何输入之前显示为函数中的前几行之一。我读到 argc
将是输入的数量。我很困惑,因为我完全复制并粘贴了教程中写的内容,但它似乎 运行ning 不正确。
该代码需要在命令行上传递文件名,而不是从标准输入中读取。您没有指定您使用的平台,但您可以在 Windows 上执行 my_program.exe C:\some\file\somewhere
或在 Linux/Mac/Other Unix 上执行 ./my_program /some/file/somewhere
,例如 OS。如果您 运行 来自 IDE 的 run/debug 函数的程序,那么您需要将其配置为将文件名作为命令行参数传递。如何做到这一点将取决于您使用的 IDE。