学说 getRepository 错误

Question

我在通过 jwt 进行身份验证时遇到问题： public 函数 getUser($credentials, UserProviderInterface $userProvider)

      {
        try {
          $credentials = str_replace('Bearer ', '', $credentials);
          $jwt = (array) JWT::decode(
            $credentials,
            $this->params->get('jwt_secret'),
            ['HS256']
          );
          return $this->em->getRepository(User::class)
            ->findOneBy([
              'username' => $jwt['user'],
            ]);
        }catch (\Exception $exception) {
          throw new AuthenticationException($exception->getMessage());
        }
      }

我有这个功能，在输入有效凭据时我收到此错误：“凭据检查失败，因为传递给 CustomCredentials 的可调用文件没有 return \u0022true\u0022。”

我想也许在 return 函数中 getRepository 想要我的用户实体存储库，我传递了参数：getRepository(UserRepository::class) 但我得到了不同的错误：class \u0027App\UserRepository\u0027 在链配置的命名空间中找不到 App\Entity

现在我有点卡住了，没有任何好主意，我将不胜感激 ides/thoguhts/clues

编辑1。我认为也许在 getRepository() 中参数应该作为字符串传递但也没有，我得到错误：Class \u0027User\u0027 不存在

编辑2。 UserRepository.php:

<?php

namespace App\Repository;

use App\Entity\User;
use Doctrine\Bundle\DoctrineBundle\Repository\ServiceEntityRepository;
use Doctrine\Persistence\ManagerRegistry;
use Symfony\Component\Security\Core\Exception\UnsupportedUserException;
use Symfony\Component\Security\Core\User\PasswordAuthenticatedUserInterface;
use Symfony\Component\Security\Core\User\PasswordUpgraderInterface;

/**
 * @method User|null find($id, $lockMode = null, $lockVersion = null)
 * @method User|null findOneBy(array $criteria, array $orderBy = null)
 * @method User[]    findAll()
 * @method User[]    findBy(array $criteria, array $orderBy = null, $limit = null, $offset = null)
 */
class UserRepository extends ServiceEntityRepository implements PasswordUpgraderInterface
{

    public function __construct(ManagerRegistry $registry)
    {
        parent::__construct($registry, User::class);
    }


    public function upgradePassword(PasswordAuthenticatedUserInterface $user, string $newHashedPassword): void
    {
        if (!$user instanceof User) {
            throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', \get_class($user)));
        }

        $user->setPassword($newHashedPassword);
        $this->_em->persist($user);
        $this->_em->flush();
    }

    // /**
    //  * @return User[] Returns an array of User objects
    //  */
    /*
    public function findByExampleField($value)
    {
        return $this->createQueryBuilder('u')
            ->andWhere('u.exampleField = :val')
            ->setParameter('val', $value)
            ->orderBy('u.id', 'ASC')
            ->setMaxResults(10)
            ->getQuery()
            ->getResult()
        ;
    }
    */

    /*
    public function findOneBySomeField($value): ?User
    {
        return $this->createQueryBuilder('u')
            ->andWhere('u.exampleField = :val')
            ->setParameter('val', $value)
            ->getQuery()
            ->getOneOrNullResult()
        ;
    }
    */
}

和User.php实体：

<?php

namespace App\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Validator\Constraints as Assert;
use Symfony\Bridge\Doctrine\Validator\Constraints\UniqueEntity;
use Symfony\Component\Security\Core\User\UserInterface;
use ApiPlatform\Core\Annotation\ApiResource;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * @ApiResource()
 * @ORM\Entity
 * @UniqueEntity(fields="email", message="Email already taken")
 * @UniqueEntity(fields="username", message="Username already taken")
 */
#[ApiResource]
class User implements UserInterface
{
    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    public $id;

    /**
     * @ORM\Column(type="string", length=255, unique=true)
     * @Assert\NotBlank()
     * @Assert\Email()
     */
    private $email;

    /**
     * @ORM\Column(type="string", length=255, unique=true)
     * @Assert\NotBlank()
     */
    private $username;

    /**
     * @Assert\NotBlank()
     * @Assert\Length(max=4096)
     */
    private $plainPassword;

    /**
     * @ORM\Column(type="string", length=64)
     */
    private $password;

    /**
     * @ORM\Column(type="array")
     */
    private $roles;

    public function __construct(){
        $this->roles = array('ROLE_USER');
    }

    public function getEmail(){
        return $this->email;
    }

    public function setEmail($email){
        $this->email = $email;
    }

    public function getUsername(){
        return $this->username;
    }

    public function setUsername($username){
        $this->username = $username;
    }

    public function getPlainPassword(){
        return $this->plainPassword;
    }

    public function setPlainPassword($password){
        $this->plainPassword = $password;
    }

    public function getPassword(){
        return $this->password;
    }

    public function setPassword($password){
        $this->password = $password;
    }

    public function getSalt(){

        return null;
    }

    public function getRoles(){
        return $this->roles;
    }

    public function eraseCredentials(){
    }
}

Answer 1

您的存储库 class 缺少一个 link。

编辑您的 @ORM\Entity 注释：

use App\Repository\UserRepository;

/**
 * @ApiResource()
 * @ORM\Entity(repositoryClass=UserRepository::class)
 * @UniqueEntity(fields="email", message="Email already taken")
 * @UniqueEntity(fields="username", message="Username already taken")
 */
#[ApiResource]
class User implements UserInterface
{

学说 getRepository 错误

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