根据各个用户的事件时差创建会话 ID

Question

我需要为个人用户根据他们触发的事件中的时间差创建会话 ID。如果两个事件之间的时间差超过 60 分钟，则特定用户的新会话 ID

User	Event_Time	Session Id
A	2016-01-01 00:00:15	1
A	2016-01-01 00:00:17	1
A	2016-01-01 00:00:27	1
B	2016-01-01 00:00:27	1
A	2016-01-01 04:01:59	2
B	2016-01-01 22:00:27	2

Answer 1

您可以使用间隙和孤岛问题的方法 - 根据与前一行的时差大小创建组（通过 lag window 函数）：

-- sample data
WITH dataset (User, Event_Time) AS (
    VALUES ('A', timestamp '2016-01-01 00:00:15'),
        ('A', timestamp '2016-01-01 00:00:17'),
        ('A', timestamp '2016-01-01 00:00:27'),
        ('B', timestamp '2016-01-01 00:00:27'),
        ('A', timestamp '2016-01-01 04:01:59'),
        ('B', timestamp '2016-01-01 22:00:27')
) 

--query
SELECT user,
    event_time,
    -- use cumulative sum as session id for group
    1 + sum(if(date_diff('minute', lag, event_time) > 60, 1, 0)) over ( partition by user order by event_time ) as session_id
FROM (
        SELECT *,
            lag(event_time) over ( partition by user order by event_time ) lag -- previous row event_time
        FROM dataset
    )

输出：

user	event_time	session_id
A	2016-01-01 00:00:15.000	1
A	2016-01-01 00:00:17.000	1
A	2016-01-01 00:00:27.000	1
A	2016-01-01 04:01:59.000	2
B	2016-01-01 00:00:27.000	1
B	2016-01-01 22:00:27.000	2

根据各个用户的事件时差创建会话 ID

Create the session IDs based on time-difference in events for individual users

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