TypeError: 'int' object is not callable, despite being a list

Question

我在 Python 中编写线性搜索代码，但似乎遇到了语法问题。

我有一个接收数组的函数，在函数内部我通过 len 函数获得了该数组的长度。问题是，尽管将数组传递给函数，但它会引发错误 'int' object is not callable.

如果有人能告诉我我做错了什么以及为什么会这样，我将不胜感激。

我在下面留下了我的代码。

from random import *

def linear_search(array, value):
    for i in range(len(array)): #line where the program raises the error
        if array[i] == value:
            i = len(array)
            return 0
    return 1

n = []
len = 25

for i in range(len):
    n.append(randint(0,100))

value = n[randint(0,24)]

result = linear_search(n, value) #calling to the function

Answer 1

这里是工作代码：

来自随机导入 *

def linear_search(array, value):
    for i in range(len(array)):  # line where the program raises the error
        if array[i] == value:
            i = len(array)
            return 0
    return 1


n = []
length = 25 #renamed this from len to length

for i in range(length):  #renamed this from len to length
    n.append(randint(0, 100))

value = n[randint(0, 24)]

result = linear_search(n, value)

您提供的代码在定义此 for 循环时存在问题：

for i in range(len):  
        n.append(randint(0, 100))

问题：var len 是 build-in 函数 len() 而不是整数

TypeError: 'int' object is not callable, despite being a list

TypeError: 'int' object is not callable, despite being a list

python

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computer-science

linear-search