如何对一列的值求和，然后使用 SQL 按另一列排序？

Question

当我 SELECT * FROM table; 我有以下结果：

+-------+--------+-------------+-------+
| state | number | candidate   | votes |
+-------+--------+-------------+-------+
| AR    |     12 | CANDIDATE A |     9 |
| AR    |     12 | CANDIDATE A |    23 |
| LA    |     12 | CANDIDATE A |    19 |
| OK    |     12 | CANDIDATE A |     2 |
| TX    |     12 | CANDIDATE A |     7 |
| TX    |     12 | CANDIDATE A |     7 |
| AR    |     25 | CANDIDATE B |     2 |
| LA    |     25 | CANDIDATE B |     5 |
| LA    |     25 | CANDIDATE B |     1 |
| OK    |     25 | CANDIDATE B |    17 |
| OK    |     25 | CANDIDATE B |    21 |
| TX    |     25 | CANDIDATE B |     7 |
| LA    |     17 | CANDIDATE C |    14 |
| LA    |     17 | CANDIDATE C |    42 |
| OK    |     17 | CANDIDATE C |    13 |
| OK    |     17 | CANDIDATE C |     5 |
| TX    |     17 | CANDIDATE C |     1 |
| TX    |     17 | CANDIDATE C |     4 |
+-------+--------+-------------+-------+

所以我尝试将总票数与 SUM(votes) as tt_votes 相加，然后将结果按候选人分组以获得 desc 顺序。

SELECT state, number, name, SUM(votes) as tt_votes 
FROM table 
GROUP BY candidate 
ORDER BY tt_votes DESC;

+-------+--------+-------------+----------+
| state | number | candidate   | tt_votes |
+-------+--------+-------------+----------+
| LA    |     17 | CANDIDATE C |       79 |
| AR    |     12 | CANDIDATE A |       67 |
| TX    |     25 | CANDIDATE B |       53 |
+-------+--------+-------------+----------+

state 列显示候选人的第一个（或最后一个？）记录，但我真正想要的不仅是按候选人分组，而且按州分组首先有一个结果是这样的：

+-------+--------+-------------+----------+
| state | number | candidate   | tt_votes |
+-------+--------+-------------+----------+
| AR    |     12 | CANDIDATE A |       32 |
| AR    |     25 | CANDIDATE B |        2 |
| AR    |     17 | CANDIDATE C |        0 |
| LA    |     17 | CANDIDATE C |       56 |
| LA    |     12 | CANDIDATE A |       19 |
| LA    |     25 | CANDIDATE B |        6 |
| OK    |     25 | CANDIDATE B |       38 |
| OK    |     17 | CANDIDATE C |       18 |
| OK    |     12 | CANDIDATE A |        2 |
| TX    |     12 | CANDIDATE A |       14 |
| TX    |     25 | CANDIDATE B |        7 |
| TX    |     17 | CANDIDATE C |        5 |
+-------+--------+-------------+----------+

它按字母顺序列出各州，然后每个州的每个候选人的 tt_votes 按 tt_votes 排序。

尝试过 UNION 或插入 WHERE state = AR 等，但没有成功。有什么想法可以做到吗？

编辑

如果我使用 (SELECT state, ANY_VALUE(number), candidate, SUM(votes) as tt_votes WHERE state = 'AR' GROUP BY state, number , candidate) UNION ((SELECT state, ANY_VALUE(number), candidate, SUM(votes) as tt_votes WHERE state = 'LA' GROUP BY state, number, candidate) UNION (SELECT state, ANY_VALUE(number), candidate, SUM(votes) as tt_votes WHERE state = 'OK' GROUP BY state, number, candidate); 等我有我们需要的东西。但是有更好的方法吗？

Answer 1

SELECT state, ANY_VALUE(number), candidate, SUM(votes) AS tt_votes   
FROM table   
GROUP BY state, candidate     
ORDER BY state, candidate;

如何对一列的值求和，然后使用 SQL 按另一列排序？

How to SUM values of a column and then order by another column using SQL?

mysql

sql

sum

sql-order-by

mariadb