Python bs4 + lxml解析table

Question

我想从这个 url - http://portal.ksada.org:8090/time-table/student?id=5598 解析 table。我最后需要得到的是某种数据结构。例如，我试图实现的目标：

class Schedule():
   date='02.02.2022' # headdate class in html
   day='Ср' # headday class in html
   lessons=[['1 пара #span lesson', '09:00-10:35', 'КомпКн[Пз]', 'ауд. 304', 'Чайка Л.Е.'],
            [...],] # div with class lessons-1 or lessons-2

所以有了它，我会确切地知道有一天会有很多课程。也许这不是最好的解决方案，也许这就是我卡住的原因。总的来说，我想要的是将所有这些东西结构化，这样我就可以得到一天、一周和一个月的课程。我尝试了很多解决方案，但只是停留在那里。我现在拥有的是这段代码：

url = 'http://portal.ksada.org:8090/time-table/student?id='
id = 5598

def get_data(url, id):
    page = requests.get(url+id)
    soup = BeautifulSoup(page.text, 'lxml')
    table = soup.select_one('table')
    items = []
    for tr in table.select('tr'):
        th_list = tr.select('th')
        td_list = tr.select('td')

        for th in th_list:
            print(th.text)
            for td in td_list:
                print(td.text.strip().replace('&nbsp', ''))

我也试过找出每一天之间的“距离”，像这样：

def get_data(url, id):
    page = requests.get(url+id)
    soup = BeautifulSoup(page.text, "html.parser")

    table = soup.find('table')
    tbody = table.find_all('tr')

    for i, t in enumerate(tbody):
            if t.find('th', class_='headday'):
                days.append(i)

并像这样使用它：

for i, d in enumerate(days[:-1]):
        for t in tbody[days[i]:days[i+1]]:

我只是不知道如何把它做得很好。

Answer 1

我希望这能帮助您找到最终的解决方案。

#Import the library - pandas
import pandas as pd

table_list=pd.read_html('http://portal.ksada.org:8090/time-table/student?id=5598',attrs = {'id': 'timeTable'},flavor='lxml')
df = table_list[0].replace(r'&nbsp','NoValue', regex=True) # replace the value with NoValue, in case needed further
df_header=['Day','W1','W2','W3','W4','W5']
df.columns=df_header # logical header 
df.head(2) # this can be commented out as this is only for data viewing

As pandas 将第一行读取为 header，将其转换为第一行数据。

#converting header to first row data
df_t=pd.DataFrame(columns=df_header, data=[table_list[0].columns.tolist()])

这是将用于数据需求的最终数据框。

df_final=df_t.append(df, ignore_index=True)
df_final.head(5) # # this can be commented out as this is only for data viewing

#setup for group weeks
week_days_notation=['Пн','Вт','Ср','Чт','Пт','Сб','Нд']
day_of_week=""
week_days=[]
for e in df_final['Day']:
    if e in week_days_notation:
        day_of_week=e
    week_days.append(day_of_week)
#week_days


# add the week_days to the dataframe
df_final.insert(0,'week_group',week_days)
df_final.head(2)

#group by week
df_final_grp=df_final.groupby('week_group')

# now can get week and  iterate in case needed
# give me only  'Wednesday':'Ср'
wed_classes=df_final_grp.get_group('Ср')
wed_classes.head(10)

其他用例：将持续时间移动到缺少它的 class。 要将 class 间隔从 Day 移动到 W1，W2 左右可以通过应用和正则表达式函数完成。

def add_date_range(row,coln):
    if "NoValue" in row[coln]: # if NoValue in  any week day return spaces
        return " "
    
    day=row['Day']
    regexp = re.compile(r'(\d{2}:\d{2}(.*)\d{2}:\d{2})+')
    r_m=regexp.search(day) # find if 14:45 format is there in Day!
    if r_m: # if 14:45 format is there if True
        class_duration=r_m[0] # get duration 14:45  16:20 from Day
        
        r_w=regexp.search(row[coln]) # search time in Week
        if r_w:
            return row[coln]
        else:
            return f"{r_m[0]}  {row[coln]}" # append duration with original value
    else:
        return row[coln] # pass the original value

df_final['W1']=df_final.apply(add_date_range,args=("W1",),axis=1)
df_final['W2']=df_final.apply(add_date_range,args=("W2",),axis=1)
df_final['W3']=df_final.apply(add_date_range,args=("W3",),axis=1)
df_final['W4']=df_final.apply(add_date_range,args=("W4",),axis=1)
df_final['W5']=df_final.apply(add_date_range,args=("W5",),axis=1)

然后应用组。

#group by week
df_final_grp=df_final.groupby('week_group')

Python bs4 + lxml解析table

Python bs4 + lxml parsing table

python

data-structures

beautifulsoup

html-table

lxml