如何将列号参数传递给 gnuplot

Question

我是运行这个脚本：

gnuplot -e "arg_xlabel='My X Label'" -e "arg_ylabel='My Y Label'" -e "arg_filename='my.csv' " -e "arg_columnindex=4" histogram.plt

除了 arg_columnindex 之外的所有参数都有效，它产生：

#!/gnuplot
#    
# Histogram of compression ratio distribution
#
set terminal postscript enhanced landscape
set output "histogram.ps"
set size ratio 0.5
set key top right
set xlabel arg_xlabel
set ylabel arg_ylabel
set style fill solid 1.0 border -1
set datafile separator ","
binwidth=0.02 # Adjust according to distribution of values in data file 
set boxwidth binwidth * 20
bin(x,width)=width*floor(x/width) + binwidth/2
plot arg_filename using (bin($arg_columnindex,binwidth)):(1.0) smooth freq with boxes t ""
# EOF

gnuplot -e "arg_xlabel='My X Labnel'" -e "arg_ylabel='My Y Label'" -e "arg_filename='my.csv'" -e "arg_columnindex=4" histogram.plt                                                              (base) 

plot arg_filename using (bin($arg_columnindex,binwidth)):(1.0) smooth freq with boxes t ""
                              ^
"histogram.plt" line 16: Column number or datablock line expected

如何传递列索引参数？

Answer 1

使用 column(arg_columnindex) 而不是 $arg_columnindex。

Answer 2

除了 Ethan 对 $arg_columnindex 的提示外，您多次指定选项 -e 的原因是什么？以下对我有用。 window 的选项 -p 持续存在（在使用 postscript 终端的情况下不需要）。

gnuplot -p -e "arg_xlabel='My X Label'; arg_ylabel='My Y Label'; arg_filename='SO70859921.dat'; arg_columnindex=4" SO70859921.gp

数据：SO70859921.dat

代码： SO70859921.gp

### calling the script from command line with arguments

set xlabel arg_xlabel
set ylabel arg_ylabel

plot arg_filename u 1:(column(arg_columnindex)) w lp pt 7
### end of code

结果：

如何将列号参数传递给 gnuplot

How to pass column number argument to gnuplot

gnuplot