如何将png保存为jpg而不将文件保存在目录中

Question

我正在使用 FromFile 从文件中获取图像，它在 FromFile 行上出现以下 png 错误：

Exception calling "FromFile" with "1" argument(s): "The given path's format is not supported."

所以，我正在尝试将 bmp 转换为 jpg，（请参阅下面 FromFile 上方的转换行）但我看到的所有示例（似乎可用）都是 saving the file. I don't want to save the file in the dir. All I need is the image format, so FromFile can use it like this example. I saw ConvertTo-Jpeg，但我不认为这是一个标准的powershell模块，不然看不到怎么安装。

我看到了 this link，但我认为这不会使图像保留 FromFile 所需的格式。

这是我的代码：

               $imageFile2 = Get-ChildItem -Recurse -Path $ImageFullBasePath -Include @("*.bmp","*.jpg","*.png") | Where-Object {$_.Name -match "$($pictureName)"}  #$imageFile | Select-String -Pattern '$($pictureName)' -AllMatches
                

                Write-Host $imageFile2
                if($imageFile2.Exists)
                {
                    if($imageFile2 -Match "png")
                    {
                        $imageFile2 | .\ConvertTo-Jpeg #I don't think this will work with FromFile below
                    }
                    $image = [System.Drawing.Image]::FromFile($imageFile2)  step
                }
                else {
                    Write-Host "$($imageFile2) does not exist"
                }

然后我把它放在excel:

  $xlsx = $result | Export-Excel -Path $outFilePath -WorksheetName $errCode -Autosize -AutoFilter -FreezeTopRow -BoldTopRow  -PassThru # -ClearSheet can't ClearSheet every time or it clears previous data  ###left off
  $ws = $xlsx.Workbook.Worksheets[$errCode]
  $ws.Dimension.Columns  #number of columns
  $tempRowCount = $ws.Dimension.Rows     #number of rows

  #only change width of 3rd column
  $ws.Column(3).Width
  $ws.Column(3).Width = 100

  #Change all row heights
  for ($row = 2 ;( $row -le $tempRowCount ); $row++)
  {
     #Write-Host $($ws.Dimension.Rows)
     #Write-Host $($row)
     $ws.Row($row).Height
     $ws.Row($row).Height = 150
     #place the image in spreadsheet
     #https://github.com/dfinke/ImportExcel/issues/1041  https://github.com/dfinke/ImportExcel/issues/993
     $drawingName = "$($row.PictureID)_Col3_$($row)" #Name_ColumnIndex_RowIndex   
     Write-Host $image
     $picture = $ws.Drawings.AddPicture("$drawingName",$image)
     $picture.SetPosition($row - 1, 0, 3 - 1, 0)
     if($ws.Row($row).Height -lt $image.Height * (375/500)) {
         $ws.Row($row).Height = $image.Height * (375/500)
     }
     if($ws.Column(3).Width -lt $image.Width * (17/120)){
        $ws.Column(3).Width = $image.Width * (17/120)
     }
  }

更新：

我只是想重申 FromFile 不能用于 png 图像。所以 Hey Scripting Guy 像这样保存图像的地方不起作用：

$image = [drawing.image]::FromFile($imageFile2)

Answer 1

我发现 $imageFile2 路径中有 2 个文件名。肯定是有两个满足了Get-ChildItem/Where-Object/match的条件。这些图像看起来相同，但名称相似，因此很容易处理。拆分名称后，FromFile 就可以了。

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