如何用杰克逊序列化这个json？

Question

我收到了 json，看起来像这样：

{
  "ref": {
    "id": "1011"
  },
  "compset": [
      {
        "id": "23412"
      },
      {
        "id": "27964"
      },
      {
        "id": "51193"
      },
      {
        "id": "74343"
      },
      {
        "id": "537157"
      },
      {
        "id": "542023"
      },
      {
        "id": "601732"
      },
      {
        "id": "793808"
      },
      {
        "id": "891169"
      },
      {
        "id": "1246443"
      }
 ],
   "isCompliant": false,
    "updateTimestamp": null,
    "remainingMilliseconds": 0,
    "totalLockoutDays": 15
}

我有三个类处理此响应：

对于“id”字段：

public class Competitor {
  @JsonProperty("id")
  @JsonFormat(shape = JsonFormat.Shape.NUMBER_INT)
  private Integer id; // this should be integer, can't change the type
}

对于“compset”字段：

public class PropertyCompetitorsModel {
  private List<Competitor> competitors;
}

对于响应本身：

public class CompSetResponse {
  @JsonProperty("compset")
  private PropertyCompetitorsModel compset;
}

如您所见，我只需要 compset 字段。

使用上面的代码我遇到了这个错误：

Cannot deserialize instance of PropertyCompetitorsModel out of START_ARRAY token

使用了 Jackson 库

Answer 1

改为使用以下内容：

public class CompSetResponse {
  @JsonProperty("compset")
  private List<Competitor> compset;
}

您当前的代码需要 JSON 如下：

{
  "ref": {
    "id": "1011"
  },
  "compset": {
    "competitors": [
        {
          "id": "23412"
        },
        {
          "id": "27964"
        },
        {
          "id": "51193"
        },
        {
          "id": "74343"
        },
        {
          "id": "537157"
        },
        {
          "id": "542023"
        },
        {
          "id": "601732"
        },
        {
          "id": "793808"
        },
        {
          "id": "891169"
        },
        {
          "id": "1246443"
        }
    ],
  },
   "isCompliant": false,
    "updateTimestamp": null,
    "remainingMilliseconds": 0,
    "totalLockoutDays": 15
}

如何用杰克逊序列化这个json？

how to serialize this json with jackson?

java

spring-boot

jackson