以行值作为列名和组连接的分组依据

Question

我正在寻找 SQL 问题的解决方案：

我这样输入 table:

RId	AId	Type
76	734	TKI
76	528	NPlat
76	735	TKI
77	713	Plat
77	749	IO
77	739	TKI
77	714	NPlat
78	518	Plat
73	519	Plat
73	518	Plat

我想要这样的输出：

RId	TKI	IO	NPlat	Plat
73				518, 519
76	734, 735		528
77	739	749	714	713
78				518

我试过 PIVOT，但它不起作用。还尝试将 GROUP BY 和 PARTITION BY 一起使用，但没有成功。

任何人都可以解决这个问题吗？

注意：我使用的是 Microsoft SQL Server 2016 (SP3)。

已编辑：我的尝试：

select 
RId,
case when Type = 'TKI' then STRING_AGG(AId, ' ') END AS TKI,
case when Type = 'IO' then STRING_AGG(AId, ' ') END AS IO,
case when Type = 'NPlat' then STRING_AGG(AId, ' ') END AS NPlat,
case when Type = 'Plat' then STRING_AGG(AId, ' ') END AS Plat
from tbl_A
group by RId, Type;

STRING_AGG 不是 SQL 服务器 2016 中的通用函数。

select 
RId,
[TKI] = COUNT(*) over(partition by Type),
[IO] = COUNT(*) over(partition by Type),
[NPlat] = COUNT(*) over(partition by Type),
[Plat] = COUNT(*) over(partition by Type)
from tbl_A
group by RId, Type
order by RId;

Answer 1

您可以先将Aid拼接成csv格式，然后进行主元

select *
from   (
           select  Rid, [Type], 
                   Aid = stuff(
                             (select ',' + convert(varchar(10), x.Aid)
                             from   tbl x 
                             where  x.Rid = t.Rid
                             and    x.[Type] = t.[Type]
                             order by x.Aid
                             for xml path('')), 1, 1, '')
           from    tbl t
           group by Rid, [Type]
       ) d
       pivot
       (
            max(Aid)
            for [Type] in ([TKI], [IO], [NPlat], [Plat])
       ) p

dbfiddle demo

Answer 2

带 Pivot 的简单使用：

SELECT RID,[TKI],[IO],[NPlat],[Plat]
FROM 
(SELECT RID,TYPE,AID = STUFF((
                                SELECT ',' + CONVERT(VARCHAR,AID)
                                FROM test t
                                WHERE t.RID = test.RID AND t.TYPE = test.type                               
                                FOR XML PATH('')
                                ), 1, 1, '')
FROM test 
)sorce
PIVOT 
( 
max(AID) FOR type IN ([TKI],[IO],[NPlat],[Plat]) 
) AS PivotTable

以行值作为列名和组连接的分组依据

Group By with row values as column name and group concat

sql-server

sql-server-2016