如何统计一个日期内所有重复5次以上的记录

Question

我试图在按用户分组的单个记录中获取在某个日期重复超过 5 次的记录的总和

这是我的查询

select user_id, answer_date, count(*) as total_mayor_que_5
from items
WHERE items.proyecto_id = 6
  and `estado` IN (1,4)
  AND `liquidada` = 1
  and items.answer_date BETWEEN '2021-01-01' and '2021-12-31'
  and items.user_id = 832
GROUP BY user_id, answer_date
HAVING COUNT(answer_date) >= 5

结果有这个

user_id	answered_date	more_greater_than_5
832	2021-11-08	6
832	2021-11-09	6
833	2021-11-09	6
833	2021-11-09	5

我不希望它显示所有这些记录；相反，我想要一个总数。例如，对于 ID 为 832 的用户，总数为 12。

这是我的结构 table 项

我想要这样的东西

user_id	total
832	12
833	11

有人可以帮助我吗？谢谢

Answer 1

您想要多一层分组

select user_id, sum(total_mayor_que_5) total
from (
    select user_id, answer_date, count(*) as total_mayor_que_5
    from items
    WHERE items.proyecto_id = 6
      and `estado` IN (1,4)
      AND `liquidada` = 1
      and items.answer_date BETWEEN '2021-01-01' and '2021-12-31'
      and items.user_id = 832
    GROUP BY user_id, answer_date
    HAVING COUNT(answer_date) >= 5
) t
GROUP BY user_id
order by user_id

如何统计一个日期内所有重复5次以上的记录

how to count all records that are repeated more than 5 times in a date

mysql

sql

phpmyadmin