如何在 node.js 中获取箭头函数的值

Question

我想获取变量“final”的值，以便能够通过套接字发送到前端

我的代码

const admin = database.collection("admin").onSnapshot(documento =>{
     const final = documento.docs.map((doc) =>({id: doc.id, ...doc.data()}))
     return final
})

const alerts = admin()

console.log(alerts);

//sockets
io.on('connection', function (socket) {
    console.log('Alguien se ha conectado con Sockets');

    socket.emit('alerts', alerts);
    socket.on('new-alert', function (data) {
        alerts.push(data);
        io.sockets.emit('alerts', alerts);
    });

}); 
//sockets

Answer 1

我会在调用 onSnapshot 时放置必要的逻辑。

const admin = database.collection("admin").onSnapshot(documento =>{
     const final = documento.docs.map((doc) =>({id: doc.id, ...doc.data()}))
     // Code that uses final here
})

Answer 2

是的，我的最终密码是

//sockets
io.on('connection', function (socket) {
    console.log('Alguien se ha conectado con Sockets');


    const admin = database.collection("admin").onSnapshot(documento =>{
        const alerts = documento.docs.map((doc) =>({id: doc.id, ...doc.data()}))

        socket.emit('alerts', alerts);
        socket.on('new-alert', function (data) {
            alerts.push(data);
            io.sockets.emit('alerts', alerts);
        });


    })

}); 
//sockets