如何迭代多行 tcl 字符串中的每一行?
How to iterate for each line in a multiline tcl string?
我有一个由几行组成的字符串:
set lines {
line 1
line 2
line 3
}
set lines [string range $lines 1 end-1]
我想执行与以下 python 代码等效的操作:
for l in lines.split('\n'):
print('line is', l)
输出:
line is line 1
line is line 2
line is line 3
tcl 解决方案与python 基本相同:使用 split 将多行字符串转换为列表。
set lines {
line 1
line 2
line 3
}
set lines [string range $lines 1 end-1]
foreach l [split $lines \n] {
puts "line is $l"
}
我有一个由几行组成的字符串:
set lines {
line 1
line 2
line 3
}
set lines [string range $lines 1 end-1]
我想执行与以下 python 代码等效的操作:
for l in lines.split('\n'):
print('line is', l)
输出:
line is line 1
line is line 2
line is line 3
tcl 解决方案与python 基本相同:使用 split 将多行字符串转换为列表。
set lines {
line 1
line 2
line 3
}
set lines [string range $lines 1 end-1]
foreach l [split $lines \n] {
puts "line is $l"
}