Python "table" 或 "matrices" 项目

Question

我的代码需要一个建议。在学校，我们正在学习如何使用 python 制作表格。我正在尝试用“1”完成反对角线，但我不知道该怎么做！

nbr_co = int(input("number of columns : "))
grid = [[0]*nbr_co for i in range(nbr_li)]

def affiche(grid):
    for i in range(nbr_li):
        print(grid[i])

for i in range():
    grid[i][] = 1
    grid[][i] = 1
affiche(grid)

这是一种输出：

[1, 0, 0, 0, 0]
[0, 1, 0, 0, 0]
[0, 0, 1, 0, 0]
[0, 0, 0, 1, 0]
[0, 0, 0, 0, 1]

Answer 1

你可以这样做：

nbr_co = int(input("number of columns : "))
nbr_li = int(input("number of lines: "))
grid = [[0]*nbr_co for i in range(nbr_li)]


def affiche(grid):
    for i in range(nbr_li):
        print(grid[i])

for i in range(nbr_co):
    grid[i][i] = 1
affiche(grid)

如果您想要另一条对角线，请这样做：

nbr_co = int(input("number of columns : "))
nbr_li = int(input("number of lines: "))
grid = [[0]*nbr_co for i in range(nbr_li)]


def affiche(grid):
    for i in range(nbr_li):
        print(grid[i])

for i in range(nbr_co):
    grid[i][(nbr_co - 1) - i] = 1
affiche(grid)

Answer 2

我明白你想做什么。首先，如果要操作对角矩阵的逆矩阵，行数和列数必须相同。

在下面的示例中，您将找到您正在尝试执行的操作的示例。

nbr_column = 4 #you can chose any number you want.
grid = []  # it's your table.
for i in range(nbr_column):
    row = [] # this variable will present a row of your table.
    for j in range(nbr_column):
        row.append(0)
    grid.append(row)

""" to display your table"""
for i in grid:
    print(i)

""" to change diagonal with 1 """
for i in range(len(grid)):
    grid[i][i] = 1

""" to display your new table"""
for i in grid:
    print(i)

Python "table" 或 "matrices" 项目

Python "table" or "matrices" project

python

project