基于区间乘数的切片

Question

我有以下值：

a = [33, 121, 230, 273, 303, 398, 445, 502, 613, 694, 721, 871, 935, 1045, 1021, 1079,
     1131, 1183]

我有一个数字200，基于这个，我要对a的值进行切片。就像 [200, 400, 600, ...] — 本质上是 200 的倍数。

我想根据 200 的倍数对 a 的值进行切片。

最终结果是以下列表：

[33, 121]
[230, 273, 303, 398]
[445, 502]
[613, 694, 721]
[871, 935]
[1045, 1021, 1079, 1131, 1183]

Answer 1

一个可能的解决方案是

cut = 200
intervals = [[k*cut, (k+1)*cut] for k in range(max(a)//cut + 1)]
[[itm for itm in a if itm > interval[0] and itm < interval[1]] for interval in intervals]

Answer 2

我的实现。

from math import ceil

a = [33, 121, 230, 273, 303, 398, 445, 502, 613, 694, 721, 871, 935, 1045, 1079, 1021, 1131, 1183]

num = 200
max_num = max(a)
divlist = [i*num for i in range(1,ceil(max_num/num)+1)]

dic = {}

for i in divlist:
    dic[i] = [x for x in a if (i-num)< x < i]

for i in divlist:
    print(dic[i])

Answer 3

这是创建范围 0-200、200-400 ... 的解决方案他们确定列表 a 中的数字是否在给定范围内

split_points = [i for i in range(0, max(a), 200)]
out: [0, 200, 400, 600, 800, 1000]

parts = [[number for number in a if number in range(split_point, split_point+200)] for split_point in split_points]

out:
[[33, 121],
 [230, 273, 303, 398],
 [445, 502],
 [613, 694, 721],
 [871, 935],
 [1045, 1079, 1021, 1131, 1183]]

Answer 4

您可以使用 itertools.groupby() 将列表中的项目分组，键为 item//200

from itertools import groupby

a = [33, 121, 230, 273, 303, 398, 445, 502, 613, 694, 721, 871, 935, 1045, 1079, 1021, 1131, 1183]
intervals = [list(g) for _, g in groupby(a, lambda x: x//200)]

输出-

[[33, 121], [230, 273, 303, 398], [445, 502], [613, 694, 721], [871, 935], [1045, 1079, 1021, 1131, 1183]]

Answer 5

虽然已经有人回答了，但这是我的解决方案

a = [33, 121, 230, 273, 303, 398, 445, 502, 613, 694, 721, 871, 935, 1045, 1079, 1021, 1131, 1183]
interval = 200
rang = range(0, max(a) + 1, interval)
b = enumerate(rang, start=1)
c = [list(filter(lambda n: (n < interval * i and n >= x), a)) for i,x in b]

输出：

[[33, 121], [230, 273, 303, 398], [445, 502], [613, 694, 721], [871, 935], [1045, 1079, 1021, 1131, 1183]]

Answer 6

过滤列表理解似乎效率很低。您可以直接计算每个值应附加到的列表：

a = [33, 121, 230, 273, 303, 398, 445, 502, 613, 694, 721, 871, 935, 1045, 1021, 1079, 1131, 1183]
step = 200

result = [[] for _ in range(max(a) // step + 1)]
for x in a:
    result[x // step].append(x)

print(result)

输出；

[[33, 121], [230, 273, 303, 398], [445, 502], [613, 694, 721], [871, 935], [1045, 1021, 1079, 1131, 1183]]

基于区间乘数的切片

Slicing based on interval multiplier

python

slice