从 javascript 数组列表中查找连续登录时间

Question

我在 javascript 中有一个对象数组，其中有员工登录时间。我想知道员工是否连续工作超过 5 小时，然后 he/she 就会休息。否则，如果员工工作超过 5 小时，但不是连续工作，则他们不会休息。

这是代码 - 它目前只检查员工的工作小时数，但不检查连续的小时数。

checkBreakTimings() {

    let breakTimes = "";
    

    const timings = [
        {
       timeIn: '11:00',
       timeOut: '12:00',        
        },
        {
       timeIn: '12:00',
       timeOut: '13:00',        
        },
        {
       timeIn: '14:00',
       timeOut: '16:00',        
        },
        {
       timeIn: '16:00',
       timeOut: '18:00',        
        }
    ];

   let h = 0;
   
      timings.forEach(e => {
        const ms = moment(e.timeOut, "HH:mm").diff(moment(e.timeIn, "HH:mm"));
        h = h + = Number(moment.duration(ms).asHours());
      });
  
      if(h > 5 )
      {
        breakTimes = "Yes";
      }
    }
    
    return breakTimes;
  }

从上面的时间可以看出，一名员工从 14:00 到 18:00 连续工作了 6 小时 8 小时，此处将应用休息时间，但以上 2 个时间是连续不超过5小时。

我的问题是 - 有什么方法可以使用 JavaScript 或 moment.js

从数组中找出连续的小时数

Answer 1

这是一个可以解决问题的函数

function isAllowedBrake(times) {
  let isAllowed = false
  let consecutive = 0;
  let lastVal

  times.forEach((e) => {
    if (lastVal && moment(lastVal, "HH:mm").isBefore(moment(e.timeIn, "HH:mm"))) {
      consecutive = 0
    }
    const ms = moment(e.timeOut, "HH:mm").diff(moment(e.timeIn, "HH:mm"));
    let duration = Number(moment.duration(ms).asHours())
    consecutive += duration
    lastVal = e.timeOut
  })

  if (consecutive > 5) {
    isAllowed = true;
  }

  return isAllowed;
}

Answer 2

像下面的片段一样尝试：

const checkBreakTimings = () => {
  let breakTimes = "";
  const timings = [
      {timeIn: '11:15', timeOut: '12:00',  },
      {timeIn: '12:00', timeOut: '13:00',  },
      {timeIn: '13:00', timeOut: '15:46',  },
      {timeIn: '16:00', timeOut: '18:00',  }
  ];
  let h = 0;
  let consecutive = 0
  let lastOut = null
  timings.forEach(e => {
    const ms = moment(e.timeOut, "HH:mm").diff(moment(e.timeIn, "HH:mm"));
    let worked = Number(moment.duration(ms).asHours())
    consecutive = worked  
    if (lastOut === e.timeIn) {  // compare if timeIn is equal to last timeOut and sum values
      consecutive += worked
    } else consecutive = 0  
    lastOut = e.timeOut
    if (consecutive > 5) breakTimes = "Yes" // it's more then 5 hours
    h = h + Number(moment.duration(ms).asHours());
  });
  console.log(breakTimes);
}
checkBreakTimings()

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从 javascript 数组列表中查找连续登录时间

Find consecutive login timings from javascript array list

javascript

vue.js

momentjs

vuejs3