如何在 payment_user_history.sid 中应用 distinct

Question

这是我在 postman 中的结果

我只想显示一个 sid，即使有 2 个结果 '''

“结果”：[ {
“席德”：2，
“编号”：2，
"user_id": "S01202100002",
"name": "FRANK AMPLE WALKER",
“LRN”：空，
"grade_level": 1
},
{
“席德”：2，
“编号”：4，
"user_id": "S01202100002",
"name": "FRANK AMPLE WALKER",
“LRN”：空，
"grade_level": 1
},
{
“席德”：3，
“编号”：3，
"user_id": "S01202100003",
"name": "NEIL DEST MORGAN",
“LRN”：空，
"grade_level": 2
}
]
}

这是我的代码

   public function billingpaymentaccount(){
    
    $fetch = DB::table('payment_user_history')
    ->leftJoin('tbl_accounts', 'payment_user_history.sid', '=', 'tbl_accounts.id')
    ->leftJoin('tbl_enrollment', 'payment_user_history.sid', '=', 'tbl_enrollment.student_id')
    ->select('payment_user_history.sid','payment_user_history.id', 'tbl_accounts.user_id', 
      DB::raw('concat(tbl_accounts.first_name, " ", tbl_accounts.middle_name, " ", 
      tbl_accounts.last_name) as name'), 'tbl_accounts.LRN', 'tbl_enrollment.grade_level')
    ->where('tbl_accounts.account_types',10)
    ->get();
    
    return response()->json(['results' => $fetch], 200);
}

Answer 1

您可以对 return 唯一行使用 ->distinct() 修饰符。但是，payment_user_history.id 需要从您的 select 语句中删除，以便查询仅 return 每个 sid 一行。

// note the added distinct
$fetch = DB::table('payment_user_history')->distinct()
->leftJoin('tbl_accounts', 'payment_user_history.sid', '=', 'tbl_accounts.id')
->leftJoin('tbl_enrollment', 'payment_user_history.sid', '=', 'tbl_enrollment.student_id')
// note the removed payment_user_history.id
->select('payment_user_history.sid', 'tbl_accounts.user_id', DB::raw('concat(tbl_accounts.first_name, " ", tbl_accounts.middle_name, " ", tbl_accounts.last_name) as name'), 'tbl_accounts.LRN', 'tbl_enrollment.grade_level')
->where('tbl_accounts.account_types',10)
->get();

如果您需要保留 payment_user_history.id 字段，那么您必须决定如何将其聚合到一行（例如，使用 max 或 min 和 group by 子句）。

如何在 payment_user_history.sid 中应用 distinct

How to apply distinct in payment_user_history.sid

join

distinct

laravel