将文本文件的一行存储为数组 python

Question

我有一个文本文件，内容如下：

我希望输出像 ["a", "1", "1"] 等，但它目前输出为

[a 1 1\n]
[b 1 1\n]
[c 1 1\n]
[d 1 1\n]
[e 1 1\n]
[f 1 1\n]

我的代码是

import csv
tname = input("player 1 enter your team name ")
x = "./" + tname + ".txt"
with open (x, "r") as r:
    reader = csv.reader(r)
    for row in r:
        spec = [row]
        print (spec)

Answer 1

无需使用 csv 模块，只需依次读取所有行，用空格分隔并将它们附加到输出列表中：

with open('input.txt', 'r') as f:
    lines = f.readlines()

output = []
for line in lines:
    output = output + line.split()

print(output)

这给你：

['a', '1', '1', 'b', '1', '1', 'c', '1', '1', 'd', '1', '1', 'e', '1', '1', 'f', '1', '1']

Answer 2

对于期望的结果是什么有些不明确。所以三个可能的答案：

with open('somefile.txt', 'r') as f:
    for row in f:
        print(row.strip().split())

# -> ['a', '1', '1']
     ['b', '1', '1']
     ['c', '1', '1']
     ['d', '1', '1']
     ['e', '1', '1']
     ['f', '1', '1']

with open('somefile.txt', 'r') as f:
    print([row.strip().split() for row in f])

# -> [['a', '1', '1'], 
      ['b', '1', '1'], 
      ['c', '1', '1'], 
      ['d', '1', '1'], 
      ['e', '1', '1'], 
      ['f', '1', '1']]

with open('somefile.txt', 'r') as f:
    print([item for row in f for item in row.strip().split()])

# -> ['a', '1', '1', 'b', '1', '1', 'c', '1', '1', 'd', '1', '1', 'e', '1', '1', 'f', '1', '1']

将文本文件的一行存储为数组 python

storing one line of a text file as an array python

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arrays

text-files