如何将 PRAW 排序参数作为函数参数？

Question

我想对各种 subreddits 进行情绪分析，并同时考虑“新”和“热门”提交。我可以通过以下方式做到这一点：

# What I have
def new_submissions(sub):
   subreddit = reddit.subreddit(sub).new(limit=100)
   for submission in subreddit:
      # Do stuff
   return new_stuff

def hot_submissions(sub):
   subreddit = reddit.subreddit(sub).hot(limit=100)
   for submission in subreddit:
      # Do stuff
   return hot_stuff

new_submissions("subname")
hot_submissions("subname")

在这里，“做事”涉及 40 行相同的代码。我想引用 subreddits 的“排序依据”参数（例如，.new()、.hot()）作为函数参数，如下所示：

# What I want
def submissions(sub, sortby):
   subreddit = reddit.subreddit(sub).sortby(limit=100)
   for submission in subreddit:
      # Do stuff
   return stuff

submissions("subname", new)
submissions("subname", hot)

我没有成功地让它工作。我该如何处理？

Answer 1

你能做的是

def submissions(subreddit):
   for submission in subreddit:
      # Do stuff
   return stuff

submissions(reddit.subreddit("subname").new(limit=100))
submissions(reddit.subreddit("subname").hot(limit=100))

或者如果您想按照您的要求去做，您可以这样做：

def submissions(sub, sortby):
    method_to_call = getattr(reddit.subreddit(sub), sortby)
    subreddit = method_to_call(limit=100)
    
    for submission in subreddit:
        # Do stuff
    return stuff
    
# new and hot are strings to search for as attributes of the class
submissions("funnyvideos", 'new')
submissions("funnyvideos", 'hot')

如何将 PRAW 排序参数作为函数参数？

How do I place a PRAW sort parameter as a function argument?

python

reddit

praw