如何获取两个不同数据框的两个地理坐标之间的距离？

Question

我正在为大学做一个项目，我有两个 pandas 数据帧：

      # Libraries
      import pandas as pd
      from geopy import distance

      # Dataframes

      df1 = pd.DataFrame({'id': [1,2,3],                   
                          'lat':[-23.48, -22.94, -23.22],
                          'long':[-46.36, -45.40, -45.80]})

       df2 = pd.DataFrame({'id': [100,200,300],                   
                           'lat':[-28.48, -22.94, -23.22],
                           'long':[-46.36, -46.40, -45.80]})

我需要计算数据帧之间的地理纬度和经度坐标之间的距离。所以我用了geopy。如果坐标组合之间的距离小于 100 米的阈值，那么我必须在 'nearby' 列中分配值 1。我编写了以下代码：

      threshold = 100  # meters

      df1['nearby'] = 0

      for i in range(0, len(df1)):
          for j in range(0, len(df2)):

              coord_geo_1 = (df1['lat'].iloc[i], df1['long'].iloc[i])
              coord_geo_2 = (df2['lat'].iloc[j], df2['long'].iloc[j])

              var_distance = (distance.distance(coord_geo_1, coord_geo_2).km) * 1000 

              if(var_distance < threshold):
                   df1['nearby'].iloc[i] = 1

虽然出现警告，但代码正常。但是，我想找到一种方法来覆盖 for() 迭代。可能吗？

       # Output:

       id   lat       long  nearby
        1   -23.48  -46.36    0
        2   -22.94  -45.40    0
        3   -23.22  -45.80    1

Answer 1

您可以 cross-merge 两个 dfs 来获得 df1 和 df2 中每个 id 之间的距离：

dfm = pd.merge(df1, df2, how = 'cross', suffixes = ['','_2'])
dfm['dist'] = dfm.apply(lambda r: distance.distance((r['lat'],r['long']),(r['lat_2'],r['long_2'])).km * 1000 , axis=1)

dfm 看起来像这样：

      id     lat    long    id_2    lat_2    long_2      dist
--  ----  ------  ------  ------  -------  --------  --------
 0     1  -23.48  -46.36     100   -28.48    -46.36  553941
 1     1  -23.48  -46.36     200   -22.94    -46.4    59943.4
 2     1  -23.48  -46.36     300   -23.22    -45.8    64095.5
 3     2  -22.94  -45.4      100   -28.48    -46.36  621251
 4     2  -22.94  -45.4      200   -22.94    -46.4   102568
 5     2  -22.94  -45.4      300   -23.22    -45.8    51393.4
 6     3  -23.22  -45.8      100   -28.48    -46.36  585430
 7     3  -23.22  -45.8      200   -22.94    -46.4    68854.7
 8     3  -23.22  -45.8      300   -23.22    -45.8        0

您可以测试列 'dist' 低于阈值，但是如果要求是从 df1 聚合 id 那么您可以做例如

res = df1.merge(dfm.groupby('id').apply(lambda g:any(g['dist'] < threshold)*1).rename('nearby'), on = 'id')

res 现在看起来像这样：

      id     lat    long    nearby
--  ----  ------  ------  --------
 0     1  -23.48  -46.36         0
 1     2  -22.94  -45.4          0
 2     3  -23.22  -45.8          1

Answer 2

如果可以使用库scikit-learn，方法haversine_distances计算两组坐标之间的距离。所以你得到：

from sklearn.metrics.pairwise import haversine_distances

# variable in meter you can change
threshold = 100 # meters

# another parameter
earth_radius = 6371000  # meters

df1['nearby'] = (
    # get the distance between all points of each DF
    haversine_distances(
        # note that you need to convert to radiant with *np.pi/180
        X=df1[['lat','long']].to_numpy()*np.pi/180, 
        Y=df2[['lat','long']].to_numpy()*np.pi/180)
    # get the distance in meter
    *earth_radius
    # compare to your threshold
    < threshold
    # you want to check if any point from df2 is near df1
    ).any(axis=1).astype(int)

print(df1)

#    id    lat   long  nearby
# 0   1 -23.48 -46.36       0
# 1   2 -22.94 -45.40       0
# 2   3 -23.22 -45.80       1

编辑：OP 要求一个与 geopy 有距离的版本，所以这是一种方法。

df1['nearby'] = (np.array(
    [[(distance.distance(coord1, coord2).km)
      for coord2 in df2[['lat','long']].to_numpy()] 
     for coord1 in df1[['lat','long']].to_numpy()]
     ) * 1000 < threshold
).any(1).astype(int)

如何获取两个不同数据框的两个地理坐标之间的距离？

How to get the distance between two geographic coordinates of two different dataframes?

geopy

dataframe

pandas