如何获得以下函数中每个元素的结果

Question

我有一个函数 return 每个词的词性以元组列表的形式。当我执行它时，我只得到第一个元素（第一个元组）的结果。我想获得该列表中每个元素（元组）的结果。例如：

get_word_pos("I am watching")

我得到的结果是：

[('I', 'PRP'), ('am', 'VBP'), ('watching', 'VBG')]
'n'

但是我想要的结果如下

"n"
"v"
"v"

我编写的函数包含多个 return 语句，这就是我只获取第一个元素作为输出的原因。如果有人可以修改我的功能以便我获得所需的输出，请。代码如下：

training = state_union.raw("2005-GWBush.txt")
tokenizer = nltk.tokenize.punkt.PunktSentenceTokenizer(training)

def get_word_pos(word):
    
    sample = word
    
    tokenized = tokenizer.tokenize(sample)
    
    
    for i in tokenized:
        words = nltk.word_tokenize(i)
        tagged = nltk.pos_tag(words)
        print(tagged)
        
    for letter in tagged:
    #print(letter[1])
        if letter[1].startswith('J'):
            return wordnet.ADJ
        elif letter[1].startswith('V'):
            return wordnet.VERB
        elif letter[1].startswith('N'):
            return wordnet.NOUN
        elif letter[1].startswith('R'):
            return wordnet.ADV
        else:
            return wordnet.NOUN
        
    ```

Answer 1

当您遍历 tagged 时，您会 return 第一项的值。你需要积累它们。将它们附加到列表中是一种方法。例如：

from nltk import word_tokenize, pos_tag
from nltk.corpus import state_union
from nltk.tokenize import PunktSentenceTokenizer
from nltk.corpus import wordnet

training = state_union.raw('2005-GWBush.txt')
tokenizer = PunktSentenceTokenizer(training)

def get_word_pos(word):
    result = []
    for token in tokenizer.tokenize(word):
        words = word_tokenize(token)
        for t in pos_tag(words):
            match t[1][0]:
                case 'J':
                    result.append(wordnet.ADJ)
                case 'V':
                    result.append(wordnet.VERB)
                case 'R':
                    result.append(wordnet.ADV)
                case _:
                    result.append(wordnet.NOUN)
    return result


print(get_word_pos('I am watching'))

输出：

['n', 'v', 'v']

如何获得以下函数中每个元素的结果

How do I get the result of every element in the following function

python

tokenize

nltk