将数据连接到单个列中
Joining Data into a Single Column
我有这个table在访问
用户信息
userid
Name
dept id
1
JJ
002
2
KK
001
部门
deptid
Dept Name
001
Testing
002
Sorting
003
Designing
签到
userid
Name
Checktime
Checktype
1
JJ
2/5/2022 7:45:10 AM
1
1
JJ
2/5/2022 18:00:10 PM
0
1
JJ
2/6/2022 6:30:00 AM
1
1
JJ
2/6/2022 18:10:30 PM
0
2
KK
2/6/2022 6:10:30 AM
1
2
KK
2/6/2022 18:20:30 PM
0
但我想创建一个将显示此内容的内部联接 table
userid
Name
Deptname
In
Out
1
JJ
Sorting
2/5/2022 7:45:10 AM
2/5/2022 18:00:10 PM
1
JJ
Sorting
2/6/2022 6:30:00 AM
2/6/2022 18:10:30 PM
1
KK
Testing
2/6/2022 6:10:30 AM
2/6/2022 18:20:30 PM
这是我用过的 SQL，但我不知道如何将 0 设为 Out，将 1 设为 In
SELECT Userinfo.userid as ID,UserInfo.Name as Name,Dept.DeptName as Dept , Checkinout.Checktime
from ( Userinfo
inner join Checkinout on Userinfo.userid = Checkinout.userid )
inner join Dept on Userinfo.DeptId =Dept.DeptId ;
从 non-normalized Checkinout 开始，您可以获得除直接 Out 之外的所有内容。然后在查询中添加一个计算字段，为每个 In Checktime 查找合适的 Out Checktime：
Out: (SELECT TOP 1 q.Checktime FROM [Checkinout] as q WHERE (q.userid = [Checkinout].[userid]) AND (q.Checktype = 0) AND (q.Checktime > [Checkinout].[Checktime])
ORDER BY q.Checktime ASC)
SQL:SELECT Userinfo.userid, Userinfo.Username, Dept.[Dept Name], Checkinout.Checktime AS [In], (SELECT TOP 1 q.Checktime FROM [Checkinout] as q WHERE (q.userid = [Checkinout].[userid]) AND (q.Checktype = 0) AND (q.Checktime > [Checkinout].[Checktime])
ORDER BY q.Checktime ASC) AS Out
FROM (Dept INNER JOIN Userinfo ON Dept.deptid = Userinfo.[dept id]) INNER JOIN Checkinout ON Userinfo.userid = Checkinout.userid
WHERE (((Checkinout.Checktype)=1))
'I used a nested query for the calculated field and calculated Out with the business rules that each user check-in must have a corresponding and later check-out by the same user without any check-in/check-outs between.
我有这个table在访问
用户信息
| userid | Name | dept id |
|---|---|---|
| 1 | JJ | 002 |
| 2 | KK | 001 |
部门
| deptid | Dept Name |
|---|---|
| 001 | Testing |
| 002 | Sorting |
| 003 | Designing |
签到
| userid | Name | Checktime | Checktype |
|---|---|---|---|
| 1 | JJ | 2/5/2022 7:45:10 AM | 1 |
| 1 | JJ | 2/5/2022 18:00:10 PM | 0 |
| 1 | JJ | 2/6/2022 6:30:00 AM | 1 |
| 1 | JJ | 2/6/2022 18:10:30 PM | 0 |
| 2 | KK | 2/6/2022 6:10:30 AM | 1 |
| 2 | KK | 2/6/2022 18:20:30 PM | 0 |
但我想创建一个将显示此内容的内部联接 table
| userid | Name | Deptname | In | Out |
|---|---|---|---|---|
| 1 | JJ | Sorting | 2/5/2022 7:45:10 AM | 2/5/2022 18:00:10 PM |
| 1 | JJ | Sorting | 2/6/2022 6:30:00 AM | 2/6/2022 18:10:30 PM |
| 1 | KK | Testing | 2/6/2022 6:10:30 AM | 2/6/2022 18:20:30 PM |
这是我用过的 SQL，但我不知道如何将 0 设为 Out，将 1 设为 In
SELECT Userinfo.userid as ID,UserInfo.Name as Name,Dept.DeptName as Dept , Checkinout.Checktime
from ( Userinfo
inner join Checkinout on Userinfo.userid = Checkinout.userid )
inner join Dept on Userinfo.DeptId =Dept.DeptId ;
从 non-normalized Checkinout 开始，您可以获得除直接 Out 之外的所有内容。然后在查询中添加一个计算字段，为每个 In Checktime 查找合适的 Out Checktime：
Out: (SELECT TOP 1 q.Checktime FROM [Checkinout] as q WHERE (q.userid = [Checkinout].[userid]) AND (q.Checktype = 0) AND (q.Checktime > [Checkinout].[Checktime])
ORDER BY q.Checktime ASC)
SQL:SELECT Userinfo.userid, Userinfo.Username, Dept.[Dept Name], Checkinout.Checktime AS [In], (SELECT TOP 1 q.Checktime FROM [Checkinout] as q WHERE (q.userid = [Checkinout].[userid]) AND (q.Checktype = 0) AND (q.Checktime > [Checkinout].[Checktime])
ORDER BY q.Checktime ASC) AS Out
FROM (Dept INNER JOIN Userinfo ON Dept.deptid = Userinfo.[dept id]) INNER JOIN Checkinout ON Userinfo.userid = Checkinout.userid
WHERE (((Checkinout.Checktype)=1))
'I used a nested query for the calculated field and calculated Out with the business rules that each user check-in must have a corresponding and later check-out by the same user without any check-in/check-outs between.