使用 void return 类型链接来自 spock 存根的副作用
Chaining side effects from spock stub with void return type
我正在尝试测试以下(人为设计的)代码,它会进行调用,如果调用失败则尝试重试一次。
public class MyObject
{
public void process(final Client client) throws IOException
{
try
{
client.send();
}
catch (IOException e)
{
client.fix();
}
try
{
client.send();
}
catch (IOException e)
{
throw new IOException(e);
}
}
public class Client
{
public void send() throws IOException {}
public void fix() {}
}
}
我的测试策略是模拟 client
对象并存根一个响应,该响应将在第一次调用 send()
时抛出异常,然后在第二次尝试时成功。
使用 spock,我有以下内容:
def "test method calls"() {
setup:
def MyObject myObject = new MyObject()
def Client client = Mock(Client)
when:
myObject.process(client)
then:
2 * client.send() >>> {throw new IOException()} >> void
}
我已经尝试了上面的方法,并将 void 替换为 null,并不断收到转换异常。
我也试过:
2 * client.send() >>> [{throw new MyException()}, void]
如何模拟我想要的回应?
本次测试通过。我添加了注释以显示每个步骤指示的内容:
def "test method calls"() {
given:
def MyObject myObject = new MyObject()
def MyObject.Client client = Mock(MyObject.Client)
//The first time client.send() is called, throw an exception
1 * client.send() >> {throw new IOException()}
//The second time client.send() is called, do nothing. With the above, also defines that client.send() should be called a total of 2 times.
1 * client.send()
when:
myObject.process(client)
then:
noExceptionThrown() //Verifies that no exceptions are thrown
1 * client.fix() // Verifies that client.fix() is called only once.
}
工作正常。
1*getName()>>"Hello"
1*getName()>>"Hello Java"
第一次调用我得到 "Hello"
。
第二次调用我得到 "Hello Java
"
我正在尝试测试以下(人为设计的)代码,它会进行调用,如果调用失败则尝试重试一次。
public class MyObject
{
public void process(final Client client) throws IOException
{
try
{
client.send();
}
catch (IOException e)
{
client.fix();
}
try
{
client.send();
}
catch (IOException e)
{
throw new IOException(e);
}
}
public class Client
{
public void send() throws IOException {}
public void fix() {}
}
}
我的测试策略是模拟 client
对象并存根一个响应,该响应将在第一次调用 send()
时抛出异常,然后在第二次尝试时成功。
使用 spock,我有以下内容:
def "test method calls"() {
setup:
def MyObject myObject = new MyObject()
def Client client = Mock(Client)
when:
myObject.process(client)
then:
2 * client.send() >>> {throw new IOException()} >> void
}
我已经尝试了上面的方法,并将 void 替换为 null,并不断收到转换异常。
我也试过:
2 * client.send() >>> [{throw new MyException()}, void]
如何模拟我想要的回应?
本次测试通过。我添加了注释以显示每个步骤指示的内容:
def "test method calls"() {
given:
def MyObject myObject = new MyObject()
def MyObject.Client client = Mock(MyObject.Client)
//The first time client.send() is called, throw an exception
1 * client.send() >> {throw new IOException()}
//The second time client.send() is called, do nothing. With the above, also defines that client.send() should be called a total of 2 times.
1 * client.send()
when:
myObject.process(client)
then:
noExceptionThrown() //Verifies that no exceptions are thrown
1 * client.fix() // Verifies that client.fix() is called only once.
}
工作正常。
1*getName()>>"Hello"
1*getName()>>"Hello Java"
第一次调用我得到 "Hello"
。
第二次调用我得到 "Hello Java
"